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3 years ago

DUE TONIGHT HELP!!!

1 answer:

5 0

Y
7
8
10

It should be simple enough that you can graph those points by yourself, with the three points at (1,7), (2,8), and (4,10). Hope I helped!

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12x > 10(2x-3) -10

KATRIN_1 [288]

Answer:

Step-by-step explanation:

12x-20x=-8x

so it would be -8x>-40

and you would divide both sides by -8

and get x<5

7 0

2 years ago

Read 2 more answers

2(x-3)-12 = -4<br> How do I solve this equations

deff fn [24]

Answer:

x= 7

Step-by-step explanation:

1st step: Multiply the factor (outside number) with the numbers and variable(s) in the box. This results in 2(x-3) = 2x-6

2nd Step: continue the rest of the equation since there are no more brackets left so 2x-6-12=-4

3rd Step: send -12 to the other side of the equation (side changes sign changes) so it will become 2x-6=-4+12 (You are actually supposed to make the variable alone on one side of the equation so that you would be able to calculate its value)

4th step: 2x-6=8 ---> send -6 to the other side as well which will then result in 2x=14

5th step: since 2 is being multiplied by x, when you send it to the other side (to make x alone) you will divide 14 by 2 ( sign of 2 changes from multiplication to division)

Final Step: x=7

3 0

3 years ago

A tool kit cost $14 for a hammer, $20 for a screwdriver set, and $11 for a measuring tape. Write two equivalent expressions for

pashok25 [27]

Answer:

Step-by-step explanation:==

8 0

2 years ago

PLZZZZZZZZZZZZZ HELP MEE

user100 [1]

Answer:

it's B

Step-by-step explanation:

2/8 = 1/4 = 0.25

1/2=0.5

0.5>0.25

so (1/2)>(1/4)

7 0

3 years ago

4x2 + 4x - 1, evaluate and fully simplify each of the - For the function f(0) following f(s + h) f(x + h) - f(5) h 10

Andrew [12]

Given the function f(x);

$f(x)=-4x^2+4x-1$

Evaluating the function f(x+h);

$\begin{gathered} f(x+h)=-4(x+h)^2+4(x+h)-1 \\ f(x+h)=-4(x^2+2xh+h^2)^{}+4(x+h)-1 \\ f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1 \end{gathered}$

So;

$f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1$

Evaluating the second function;

$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1-(-4x^2+4x-1)}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1+4x^2-4x+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2+4x^2-4h^2-8xh^{}+4x-4x+4h-1+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h} \end{gathered}$

simplifying further;

$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h}=-4h-8x+4 \\ \frac{f(x+h)-f(x)}{h}=-4h-8x+4 \end{gathered}$

Therefore, we have;

$undefined$

7 0

11 months ago