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3 years ago

DUE TONIGHT HELP!!!

1 answer:

5 0

Y
7
8
10

It should be simple enough that you can graph those points by yourself, with the three points at (1,7), (2,8), and (4,10). Hope I helped!

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Estimate the quotient when 29,376 is divided by 29

Mnenie [13.5K]

The Quotient would be 1012 so I would just put 1000 if your supposed to estimate.

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3 years ago

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Assume that the lines that appear to be tangent are tangent p is the center if each circle find x.

Elodia [21]

Answer:

Step-by-step explanation:

Problem One

All quadrilaterals have angles that add up to 360 degrees.

Tangents touch the circle in such a way that the radius and the tangent form a right angle at the point of contact.

Solution

x + 115 + 90 + 90 = 360

x + 295 = 360

x + 295 - 295 = 360 - 295

x = 65

Problem Two

From the previous problem, you know that where the 6 and 8 meet is a right angle.

Therefore you can use a^2 + b^2 = c^2

a = 6

b =8

c = ?

6^2 + 8^2 = c^2

c^2 = 36 + 64

c^2 = 100

sqrt(c^2) = sqrt(100)

c = 10

x = 10

Problem 3

No guarantees on this one. I'm not sure how the diagram is set up. I take the 4 to be the length from the bottom of the line marked 10 to the intersect point of the tangent with the circle.

That means that the measurement left is 10 - 4 = 6

x and 6 are both tangents from the upper point of the line marked 10.

Therefore x = 6

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3 years ago

How many degrees must the temperature increase to reach 0 ?

miv72 [106K]

Answer:

D because if you add 10 to negative ten the cancel out and make 0

Step-by-step explanation:

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3 years ago

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Solve x^2 + 5x + 6 = 0

grigory [225]

Answer:

(x+3)(x+2)

Step-by-step explanation:

take x^2 and take it apart. so it should be (x+ ) (x+ ) then take 6 and make it so it's multipuls equal 5. ur answer should be (x+3)(x+2) or vice versa.

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3 years ago

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A population of monkeys' tail lengths is normally distributed with a mean of 25 cm with a standard deviation of 8 cm. I am prepa

Crank

Answer:

The probability that the mean of my sample will be between 24 and 25 cm

P(24 ≤X⁻≤25) = 0.4772

Step-by-step explanation:

Step(i):-

Given mean of the Population 'μ'= 25c.m

Given standard deviation of the Population 'σ' = 8c.m

Given sample size 'n' = 256

Let X₁ = 24

$Z_{1} = \frac{x_{1}-mean }{\frac{S.D}{\sqrt{n} } } = \frac{24-25}{\frac{8}{\sqrt{256} } } = -2$

Let X₂ = 25

$Z_{2} = \frac{x_{2}-mean }{\frac{S.D}{\sqrt{n} } } = \frac{25-25}{\frac{8}{\sqrt{256} } } = 0$

Step(ii):-

The probability that the mean of my sample will be between 24 and 25 cm

P(24 ≤X⁻≤25) = P(-2≤ Z ≤0)

= P( Z≤0) - P(Z≤-2)

= 0.5 + A(0) - (0.5- A(-2))

= A(0) + A(2) ( ∵A(-2) =A(2)

= 0.000+ 0.4772

= 0.4772

Final answer:-

The probability that the mean of my sample will be between 24 and 25 cm

P(24 ≤X⁻≤25) = 0.4772

4 0

3 years ago