Helen runs the longest distance in 4 days.
Helen (In 4 days): 2.75 x 4 = 11
Bill (In 4 days): 10
11 (Helen) > 10 (Bill), so therefore Helen runs the longest distance in 4 days.
A - 2x^2 + 2x - 2
To find this, set up the equation:
(-x^2 + 6x - 1) + ( 3x^2 - 4x - 1)
With this, you need to combine like terms while taking into consideration the addition sign.
-x^2 + 3x^2 = 2x^2
6x + - 4x = 2x
- 1 + - 1 = - 2
Hope this helps!
<em><u>7/6 is the right answer.</u></em> First you had to add by the fractions. And it gave us, 
. Since the denominators are equal, combine the fractions. And it gave us, 
. Finally, you had to add by the numbers, and it gave us the answer is 2+5=7, or 7/6 is the right answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie
Answer:
We do not have enough evidence to accept H₀
Step-by-step explanation:
Normal Distribution
size sample = n = 64 (very small sample for evaluating population of 5 years
Standard deviation 4,8
1.- Test hypothesis
H₀ null hypothesis ⇒ μ₀ = 14 and
Hₐ alternative hypothesis ⇒ μ₀ ≠ 14
2.- z(c) we assume α = 0,05 as we are dealing with a two test tail we should consider α/2 = 0.025.
From z table we the z(c) value
z(c) = 1.96 and of course by symmetry z(c) = -1.96
3.- We proceed to compute z(s)
z(s) = [ ( μ - μ₀ ) /( σ/√n) ] ⇒ z(s) = - (1.5)*√64/4.8
z(s) = - 2.5
We compare z(s) and z(c)
z(s) < z(c) -2.5 < -1.96 meaning z(s) is in the rejection zone
we reject H₀ .
From the start we indicate sample size as to small for the experiment nonetheless we found that we dont have enough evidence to accept H₀
Step-by-step explanation:
P(X)=2x²-5x-3 is in the form ax²+bx+c
Using quadratic equation
x={-b±√(b²-4ac)}/2a
x=3,-1/2
