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Sergeu [11.5K]
3 years ago
15

para alumbrar un parque, se colocan luminarias a lo largo de una longitud de 100 metros, si la primera se coloca en el metro 1,

la siguiente en el metro 4, la que sigue en el metro 7, y así sucecibamente. en las siguientes posiciones se colocará una luminaria exepto en el metro: a)13 b)19 c) 21 d)28 ayudaaaaaaa​
Mathematics
1 answer:
Ahat [919]3 years ago
6 0

Answer:

c)21

Step-by-step explanation:

"To light a park, luminaries are placed along a length of 100 meters, if the first is placed in meter 1, the next in meter 4, the next in meter 7, and so on. in the following positions a luminary will be placed except in the subway:

a)13 b)19 c) 21 d)28? "

-------------

Luminaries position:

  • 1, 4, 7, ...

It makes an AP with the first term of 1 and common difference of 3

The formula for this AP is:

  • aₙ = 1 + 3(n-1) = 1 + 3n - 3 = 3n - 2

From the given options, only one is not in the same format:

  • c) 21

because

  • 21 = 3n - 2 ⇒ 3n = 23 and n= 23/3 is not an integer

Answer is: c) 13

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The cost of attending an amusement park is $10 for children and $20 for adults. On a particular day, the attendance at the amuse
Lapatulllka [165]

Using a system of equations, it is found that 10,000 children attended the park that day.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

  • Variable c: Number of children in the park.
  • Variable a: Number of adults in the park.

The attendance at the amusement park is 30,000 attendees, hence:

c + a = 30,000, which is the first equation in matrix form.

Then:

a = 30,000 - c

The cost of attending an amusement park is $10 for children and $20 for adults. The total money earned by the park is $500,000, hence:

10c + 20a = 500,000, which is the second equation in matrix form.

Since a = 30,000 - c, we replace:

10c + 20a = 500,000

10c + 20(30000 - c) = 500,000

10c = 100,000

c = 10,000.

More can be learned about a system of equations at brainly.com/question/24342899

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What is 452 X 652 + 79
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ANSWER: 294,783

452*652=294,704

294,704+79=294,783
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What is/are the variable(s) in this expression: 6a-7b+8
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Step-by-step explanation:

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The mean amount purchased by a typical customer at Churchill's Grocery Store is $26.00 with a standard deviation of $6.00. Assum
Vadim26 [7]

Answer:

a) 0.0951

b) 0.8098

c) Between $24.75 and $27.25.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 26, \sigma = 6, n = 62, s = \frac{6}{\sqrt{62}} = 0.762

(a)

What is the likelihood the sample mean is at least $27.00?

This is 1 subtracted by the pvalue of Z when X = 27. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{27 - 26}{0.762}

Z = 1.31

Z = 1.31 has a pvalue of 0.9049

1 - 0.9049 = 0.0951

(b)

What is the likelihood the sample mean is greater than $25.00 but less than $27.00?

This is the pvalue of Z when X = 27 subtracted by the pvalue of Z when X = 25. So

X = 27

Z = \frac{X - \mu}{s}

Z = \frac{27 - 26}{0.762}

Z = 1.31

Z = 1.31 has a pvalue of 0.9049

X = 25

Z = \frac{X - \mu}{s}

Z = \frac{25 - 26}{0.762}

Z = -1.31

Z = -1.31 has a pvalue of 0.0951

0.9049 - 0.0951 = 0.8098

c)Within what limits will 90 percent of the sample means occur?

50 - 90/2 = 5

50 + 90/2 = 95

Between the 5th and the 95th percentile.

5th percentile

X when Z has a pvalue of 0.05. So X when Z = -1.645

Z = \frac{X - \mu}{s}

-1.645 = \frac{X - 26}{0.762}

X - 26 = -1.645*0.762

X = 24.75

95th percentile

X when Z has a pvalue of 0.95. So X when Z = 1.645

Z = \frac{X - \mu}{s}

1.645 = \frac{X - 26}{0.762}

X - 26 = 1.645*0.762

X = 27.25

Between $24.75 and $27.25.

3 0
3 years ago
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