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Vedmedyk [2.9K]
3 years ago
15

What is the systematic name of PbO?

Chemistry
2 answers:
lilavasa [31]3 years ago
6 0
Lead Oxide

Pb is Lead

O is Oxygen

I hope this helped
vazorg [7]3 years ago
3 0
Lead (II) Oxide because lead occurs in both +2 and +4 oxidation states
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Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it
Sauron [17]

Answer:

The concentration of COF₂ at equilibrium is 0.296 M.

Explanation:

To solve this equilibrium problem we use an ICE Table. In this table, we recognize 3 stages: Initial(I), Change(C) and Equilibrium(E). In each row we record the <em>concentrations</em> or <em>changes in concentration</em> in that stage. For this reaction:

   2 COF₂(g) ⇌ CO₂(g) + CF₄(g)

I      2.00              0              0

C      -2x              +x            +x

E   2.00 - 2x         x              x

Then, we replace these equilibrium concentrations in the Kc expression, and solve for "x".

Kc=8.30=\frac{[CO_{2}] \times [CF_{4}] }{[COF_{2}]^{2} } =\frac{x^{2} }{(2.00-2x)^{2} } \\8.30=(\frac{x}{2.00-2x} )^{2} \\\sqrt{8.30} =\frac{x}{2.00-2x}\\5.76-5.76x=x\\x=0.852

The concentration of COF₂ at equilibrium is 2.00 -2x = 2.00 - 2 × 0.852 = 0.296 M

6 0
3 years ago
Draw a basic atom (Bohr model showing me where everything is located in the above chart).
tino4ka555 [31]

Answer:

thhe anwer is d

Explanation:

the answer is d just took the quiz got 100 on edge 2022

6 0
2 years ago
If excess sodium sulfate react with 36 g of iron (III) phosphate and produce a 65.0% yield of sodium phosphate, how many grams o
Dennis_Churaev [7]

Answer:

According to the stoichiometry, the theoretical yield is 11.5 grams. Multiplying this by 0.650, you get 7.48 grams.

Explanation:

5 0
3 years ago
Sterling silver is:
dexar [7]

Answer:

It’s D

Explanation:

It’s an alloy so it is not pure. If you take a small sample and analyze it, the mixture will be similar throughout. Think of Gatorade as a homogeneous mixture because it is the same concentration of all ingredients throughout. Think of pizza for heterogeneous mixtures. There isn’t the pepperoni (or whatever you prefer) throughout.

4 0
3 years ago
A 0.15 mol sample of H2S is placed in a 10 L reaction vessel and heated to 1132◦C. At equilibrium, 0.03 mol H2is present. Calcul
Angelina_Jolie [31]

Answer: The value of the equilibrium constant is 0.00009.

Explanation:

Initial moles of  H_2S = 0.15 mole

Volume of container = 10 L

Initial concentration of H_2S=\frac{moles}{volume}=\frac{0.15moles}{10L}=0.015M  

Moles of H_2 at equilibrium= 0.03 mole

equilibrium concentration of H_2=\frac{moles}{volume}=\frac{0.03moles}{10L}=0.003M [/tex]

The given balanced equilibrium reaction is,

                            2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

Initial conc.           0.015 M                     0     0

 At eqm. conc.    (0.015-2x) M           (2x) M   (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}

K_c=\frac{(2x)^2\times x}{(0.015-2x)^2}

we are given : 2x= 0.003 M

x= 0.0015 M

Now put all the given values in this expression, we get :

K_c=\frac{(0.003)^2\times 0.0015}{(0.015-0.003)^2}

K_c=0.00009

Thus the value of the equilibrium constant is 0.00009.

8 0
3 years ago
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