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Dominik [7]
3 years ago
11

Work out the length of BC.

Mathematics
1 answer:
Akimi4 [234]3 years ago
3 0
The length of BC is 53 units long
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A NASA spacecraft once landed on the surface of the asteroid named 433 Eros.This asteroid is near Earth and has an average orbit
Vinvika [58]
It would be 24,360 meters per second
6 0
3 years ago
David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o
BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :(b^4,b^2,b^4)

b^4= b × b × b × b

b^2 = b × b

b^4 =b × b × b × b

GCF of variables :(b^4,b^2,b^4) is b^2

3) GCF of c^3 and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) 80b^4-32b^2c^3+48b^4c

=16b^2(5b^2-2c^3+3b^2c)

David applied the distributive property.

7 0
3 years ago
Read 3 more answers
which statement is true about the equations –3x 4y = 12 and x1/4 – 1/3y = 1? the system of the equations has exactly one solutio
finlep [7]
If you would like to solve the system of equations, you can do this using the following steps:

-3x + 4y = 12
x * 1/4 - 1/3 * y = 1 ... x * 1/4 = 1 + 1/3 * y ... x = 4 + 4/3 * y
_____________
<span>-3x + 4y = 12
</span>-3 * (4 + 4/3 * y) + 4y = 12
-12 - 4y + 4y = 12
-12 = 12
-12 - 12 = 0
-24 = 0

The correct result would be: <span>the system of the equations has no solution; the two lines are parallel.</span>
4 0
3 years ago
HURRY TEACHER DIDN'T PUT ON STUDY GUIDE
Andru [333]

1 step: Place the point of the compass on point M and draw an arc, making sure the width of the compass opening is greater than 1/2MN.

2 step: Place the point of the compass on point N and draw an arc that has the same radius as previous one.

3 step: Connect two points of intersection of drawn arcs. Obtained line will be bisector.

Answer: option D.

5 0
3 years ago
Read 2 more answers
If BTS=GHD BS=25 TS=14 BT=31 GD=4x-11 S=56 B=21 and H=(7y+5) find the values of x and y
77julia77 [94]

Given:

Consider the completer question is "If ∆BTS≅∆GHD, BS=25, TS=14, BT=31, GD=4x-11, m∠S=56, m∠B=21 and m∠H=(7y+5), find the values of x and y.

To find:

The values of x and y.

Solution:

We have,

\Delta BTS\cong \Delta GHD       (Given)

BS=GD                       (CPCTC)

25=4x-11

25+11=4x

36=4x

Divide both sides by 4.

9=x

In ∆BTS,

\angle B+\angle T+\angle S=180^\circ    (Angle sum property)

21^\circ+\angle T+56^\circ=180^\circ

77^\circ+\angle T=180^\circ

\angle T=180^\circ-77^\circ

\angle T=103^\circ

Now,

\angle T=\angle H            (CPCTC)

103=7y+5

103-5=7y

98=7y

Divide both sides by 7.

14=y

Therefore, the value of x is 9 and value of y is 14.

3 0
3 years ago
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