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Dominik [7]
3 years ago
11

Work out the length of BC.

Mathematics
1 answer:
Akimi4 [234]3 years ago
3 0
The length of BC is 53 units long
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I have trouble with these two questions, even i did my equation but i don’t get the answers
Sophie [7]

Answer:

$318.17, out of state college is $161.12 cheaper per month

Step-by-step explanation:

72*24 = 1728 + 410*4 = 1728 + 1640 = 3368 + 450 = 18/12 = $318.17

8700+650*9 = 8700 + 5850 = 14550/9 = 1616.66

8500+400*9 = 8500 + 3600 = 12100 + 1000 = 13100/9 = 1455.56

1616.67 - 1455.56= $161.11 (use $161.12)

3 0
2 years ago
What is the area of a regular octagon with an apothem 16 inches long and a side 19 inches long? round the answer to the nearest
vichka [17]
The area of a regular octagon is given by:
 A = (4) * (L) * (ap)
 Where,
 L: side
 ap: apotema
 Substituting values we have:
 A = (4) * (19) * (16)
 A = 1216 square inches
 Answer:
 
The area of a regular octagon with an apothem 16 inches long and a side 19 inches long is:
 
A = 1216 square inches
8 0
3 years ago
Alexis wanted to understand whether grade level had any relationship to their opinion on extending the school day. She surveyed
MakcuM [25]

Actually there is enough information to solve this problem. First, let us find the total per row and per column.


 (see attached pic)


P(Grade 10 | opposed) with P(opposed | Grade 10)

P(Grade 10 | opposed) = Number in Grade 10 who are opposed / Total number of Opposed (column)

P(Grade 10 | opposed) = 13 / 41 = 0.3171

 

P(opposed | Grade 10) = Number in Grade 10 who are opposed / Total number in Grade 10 (row)

P(opposed | Grade 10) = 13 / 32 = 0.4063

 

Therefore:

P(Grade 10 | opposed) IS NOT EQUAL P(opposed | Grade 10), hence they are dependent events.

 

Answer:

P(Grade 10 | opposed) < P(opposed | Grade 10)

6 0
3 years ago
Read 2 more answers
Help please. I dont understand it..so I cant explain it
Ann [662]
A)
x^2 - 6x + c = - 5 + c

using a^2 - 2ab + b^2 = (a-b)^2
so
6x = 2 * x * 3
so
c = 9 

Answer
c = 9

b)
substitute c = 9
x^2 - 6x +  9 = - 5 + 9
(x - 3)^2 = 4

Answer:
(x - 3)^2 = 4

c) solve for x

(x - 3)^2 = 4
(x - 3)^2 = 2^2
so
x - 3 = 2  
     x = 5

and

x - 3 = -2
     x = 1

Answer: x = 1 , 3


8 0
3 years ago
Will give brainliest! Help me solve this logs problem!! Thank you​
Anon25 [30]

Answer:

4

Step-by-step explanation:

solving equation 1

  • log125 base 5√5=x
  • [5√5=√(25×5)=√125]
  • log125 base 125=x
  • [From one of the principles of logarithm " logA base a =1]
  • therefore, log125 base 125=1
  • x=1

solving equation 2

  • log 64 base 2√2=y
  • [2√2=√(4×2)=√8]
  • log 64 base√8=y
  • 64=(√8)^y
  • 64=8^(½y)
  • 8²=8^(½y)
  • (8 cancels in both equations and I evaluate the powers figures)
  • 2=½y
  • y=2×2=4

the product of x and y=x•y=1×4=4

4 0
3 years ago
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