Answer:
Is there a graph?
Step-by-step explanation:
Answer:
Step-by-step explanation:
1) Least common denominator of 4 and 2 is 4
To eliminate the fraction, each term should be multiplied by 4
ANS:option c
2) Mercury level of water 'y' years = Initial measure +rate of increase 'y' years
0.05 +0.1y = 0.12+0.06y
Ans : Option c
3) 4b +6 = 2 - b + 4
Add 'b' to both sides
4b + b + 6 = 2 + 4
5b + 6 = 6
Subtract 6 from both sides
5b = 6 - 6
5b = 0
b = 0
Ans : Option b
4) Maximum decimal places in this equation is 2. So, to eliminate decimal places, The equation should be multiplied by 100
Ans: option d
5) y +6 = -3y + 26
Add 3y to both the sides
y + 6 + 3y = 26
y + 3y + 6 = 26
4y + 6 = 26
Subtract 6 from both sides
4y = 26-6
4y = 20
Divide bothe sides by 4
y = 20/4
y = 5
Ans: option c
6) '2x' is subtracted from both side of the equation.
Ans: option a - subtraction property of equality
Answer: The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
Step-by-step explanation: this is the same paragraph The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
It is the bottom right corner choice
Answer:
3 18/25, 4.725, 19/4, 4.87
Step-by-step explanation:
