Ask question

Ask question

All categories

3 years ago

8

Solve for w. W + 33 = 67 W =

1 answer:

Margaret [11]3 years ago

7 0

Answer:

The answer is 34, bec what you do is: 67 - 33.

You might be interested in

What is the slope of a line that is perpendicular to y=1/2x+9 that passes through (-7,-4)

Artist 52 [7]

Hi there!

To find the perpendicular slope you need to flip the fraction and change the sign. So 1/2=2/1 and tge original slope was positive, so the slope is -2. Now you sub in the point (-7,-4) in for x and y in the formula y=mx+b and solve for b (sub in 2 for m as well)
Y=mx+b
-4=-2*-7+b
-4=14+b
-4-14=b
B=-18
The equation is y=-2x-18

Hope this helps!

6 0

3 years ago

QUESTION 2<br>Simplify the following<br>a5×a7

Kryger [21]

Answer:

$a^{12}$

Step-by-step explanation:

<em><u>Identity Used </u></em>: $a^x \times a^y = a^{x+ y}$

$a^5 \times a^7 = a^{5 + 7} = a^{12}$

6 0

3 years ago

Read 2 more answers

A shop keeper bought 26 apples from a fruit vendor for $37.70. How much did each apple cost?

Semenov [28]

You have to divide 37.70. By 26

3 0

3 years ago

Read 2 more answers

What is the slope of this graph?<br> a. 4<br> b. -4<br> c. -1/4 <br> d. 1/4

kykrilka [37]

The answer is -4 i just did the test

6 0

3 years ago

A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?

kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

$f(x)=\frac{1}{2^{2x}}$ (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

$\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]$ (2)

To solve this derivative you use the following derivative formula:

$\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}$

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

$\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)$

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

$-2(ln2)2^{-2x}=-1$

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

$-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235$

With this value you calculate f(a):

$f(a)=\frac{1}{2^{2(0.235)}}=0.721$

Next, you use the general equation of line:

$y-y_o=m(x-x_o)$

for xo = a = 0.235 and yo = f(a) = 0.721:

$y-0.721=(-1)(x-0.235)\\\\y=-x+0.956$

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

$0=-x+0.956\\\\x=0.956$

hence, the x-intercept of the tangent line is 0.956

5 0

3 years ago