Which type of communication is usually handwriten

One of the disadvantages of Photoshop Express is that it does not have a Black and White effect. True False

Katarina [22]

False,
The Pop Color tool can be used to select one particular color, changing the rest of the image to black and white. The effects available in Photoshop Express don't allow for a huge amount of customization

8 0

3 years ago

Create a class Str that subclasses str. Add a method to the subclass that checks if the string does not start with a given strin

Stolb23 [73]

Answer:

#include <iostream>

using namespace std;

class Str{ ///baseclass

public :

string super_str;

string getStr()

{

return super_str;

}

void setStr(string String)

{

super_str=String;

}

};

class str : public Str{ //inheriting Str publicly

public :

string sub_str;

string getstr()

{

return sub_str;

}

void setstr(string String)

{

sub_str=String;

}

bool notstartswith()

{

int n=sub_str.length(); //to find length of substr

bool flag=false;

for(int i=0;i<n;i++) //Loop to check beginning of Str

{

if(super_str[i]!=sub_str[i])

{

flag=true;

break;

}

return flag;

}

};

int main()

{

str s; //object of subclass

s.setStr("Helloworld");

s.setstr("Hey");

if(s.notstartswith()==1) //checking if str is substring of Str

cout<<"Str does not start with str";

else

cout<<"Str starts with str";

return 0;

}

OUTPUT :

Str does not start with str

Explanation:

Above program is implemented the way as mentioned. for loop is being used to check the beginning of the str starts with substring or not.

3 0

3 years ago

Write a program that reads a list of words. Then, the program outputs those words and their frequencies. Ex: If the input is: he

Tpy6a [65]

Answer:

#Declare variable to get the input

#list from the user

input_list = input()

#split the list into words by space

list = input_list.split()

#Begin for-loop to iterate each word

#to get the word frequency

for word in list:

#get the frequency for each word

frequency=list.count(word)

#print word and frequency

print(word,frequency)

Explanation:

This program that we are told to write will be done by using python programming language/ High-level programming language.

The question wants us to write a program in which the output will be as below;

hey 1

hi 2

Mark 1

hi 2

mark 1

Just by imputing hey hi mark hi mark.

Just copy and run the code below.

#Declare variable to get the input

#list from the user

input_list = input()

#split the list into words by space

list = input_list.split()

#Begin for-loop to iterate each word

#to get the word frequency

for word in list:

#get the frequency for each word

frequency=list.count(word)

#print word and frequency

print(word,frequency)

4 0

3 years ago

Integers and booleans. Write a program RightTriangle that takes three int command-line arguments and determines whether they con

icang [17]

Answer:

The programming language is not stated;

I'll answer using C++

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

int side1, side2, side3;

cout<<"Enter the three sides of the triangle: "<<endl;

cin>>side1>>side2>>side3;

if(side1<=0 || side2 <= 0 || side3 <= 0) {

cout<<"Invalid Inputs";

}

else {

if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) {

cout<<"Right Angled";

}

else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) {

cout<<"Right Angled";

}

else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) {

cout<<"Right Angled";

}

else {

cout<<"Not Right Angled";

}

return 0;

}

Explanation:

The following line declares the three variables

int side1, side2, side3;

The next line prompts user for input of the three sides

cout<<"Enter the three sides of the triangle: "<<endl;

The next line gets user input

cin>>side1>>side2>>side3;

The following if condition checks if any of user input is negative or 0

if(side1<=0 || side2 <= 0 || side3 <= 0) {

cout<<"Invalid Inputs";

}

If otherwise

else {

The following if condition assumes that side1 is the largest and test using Pythagoras Theorem

if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) {

cout<<"Right Angled";

}

The following if condition assumes that side2 is the largest and test using Pythagoras Theorem

else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) {

cout<<"Right Angled";

}

The following if condition assumes that side3 is the largest and test using Pythagoras Theorem

else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) {

cout<<"Right Angled";

}

If none of the above conditions is true, then the triangle is not a right angles triangle

else {

cout<<"Not Right Angled";

}

}

return 0;

Download cpp

4 0

3 years ago

Barat explains that if you have a cell that is the sales price of a given product, the value of which will change to produce the

Mice21 [21]

Answer Choices:

a.goal cell

b.constraint

c.changing cell

d.absolute cell

Answer:

c.changing cell

4 0

3 years ago