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kompoz [17]
3 years ago
6

Please explain me how to solve it cos2x+cos4x ≥0

Mathematics
1 answer:
Sliva [168]3 years ago
3 0
2x + 4x will always be larger or equal to 0.
if x= 0 than it will be equal to 0.
Does this help at all?

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Jewli Jewli planted a rectangular garden that is 20 feet long she plays 56 feet of the fencing around her garden draw and label
Veronika [31]
Is 56 great time to get
4 0
3 years ago
Solve the equation. <br> 5/6 x-4 = -2
lora16 [44]

Answer:

2 2/5

Step-by-step explanation:

5/6 x-4 = -2

Add 4 to each side

5/6 x-4+4 = -2+4

5/6 x = 2

Multiply by 6/5 to isolate x

6/5 *5/6 x = 6/5 *2

x = 12/5

Changing this from an improper fraction

5 goes into 12   2 times with 2 left over

x = 2  2/5

7 0
4 years ago
The length of a rectangle is 4 meters less than twice its width. The are of a rectangle is 70m^2. Find the dimensions of the rec
igomit [66]

Answer:

The length is 7 m

The width is 10 m

Step-by-step explanation:

length = x

width = 2x - 4

length * width = area

It is given that the area is 70 m^{2}

From there

x * (2x - 4) = 70

2x^{2} - 4x = 70

2x^{2} - 4x - 70 = 0

x^{2} - 2x - 35 = 0

Now we have a quadratic equation, which is  ax^{2} + bx + c = 0, where a \neq 0

In this equation a = 1, b = -2 and c = -35

Discriminant (D) formula is b² - 4ac

D = -2^{2}  - 4 * 1 * (-35) = 144 > 0

This discriminant is more than 0, so there are two possible x

Their formulas are  \frac{- b - \sqrt{D}  }{2a} and \frac{- b + \sqrt{D}  }{2a}

x_{1} =  \frac{- (-2) - \sqrt{144} }{2} = -5 < 0 (the length of the rectangle has to be more than 0, so we don't use this x)

x_{2} = \frac{- (-2) + \sqrt{144} }{2} = 7 > 0 (this one is right)

Calculating the dimensions

length = x = 7 (m)

width = 2x - 4 = 2 * 7 - 4 = 10 (m)

8 0
3 years ago
Which is the best estimate for the diagonal of a rectangle with a width of x and a length of 2x, if x is 1.33?
german

The best estimate for the diagonal of the rectangle is 3 ⇒ B

Step-by-step explanation:

In a rectangle:

  • The length and the width are perpendicular
  • The length of its diagonal = \sqrt{(length)^{2}+(width)^{2}} (the diagonal is the hypotenuse of a right triangle whose legs are the length and the width of the rectangle)

∵ The width of a rectangle = x

∵ The length of the rectangle = 2x

∵ The diagonal = \sqrt{(length)^{2}+(width)^{2}}

- Substitute the length by 2x and the width by x

∴ The diagonal = \sqrt{(2x)^{2}+(x)^{2}}

∴ The diagonal = \sqrt{4x^{2}+x^{2}}

∴ The diagonal = \sqrt{5x^{2}}

∵ x = 1.33

- Substitute the value of x by 1.33 to find the diagonal

∴ The diagonal = \sqrt{5(1.33)^{2}}

∴ The diagonal = 2.973

∴ The diagonal ≅ 3

The best estimate for the diagonal of the rectangle is 3

Learn more:

You can learn more about the rectangles in brainly.com/question/13084321

#LearnwithBrainly

6 0
3 years ago
How do you find out if a ratio is equivalent
Keith_Richards [23]
One way is to turn them into fractions and simplify them then see if they are equal exg
8:4 and 6:3
turn into fractions
8/4 and 6/3
2/1 and 2/1
equal
7 0
4 years ago
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