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3 years ago

Determine the value of the unknown 374=11(2n+8)

Mathematics

2 answers:

denis23 [38]3 years ago

5 0

Answer:

n=13

Step-by-step explanation:

Distribute the 11 on the right sides of the equation

374=11(2n+8)

374=22n+88

Subtract 88 from both sides

286=22n

Divide by 22 on both both sides

13=n

Hope this helps! :)

IgorLugansk [536]3 years ago

4 0

Answer:

n = 13

Step-by-step explanation:

374 = 11(2n+8)

Expand the right side

374 = 11* 2n + 11 * 8

374 = 22n + 88

Subtract 88 from both sides

374 - 88 = 22n

286 = 22n

divide both sides by 22

n = 13

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(X^2+ x– 12) (x^2+ 10x + 25)

yulyashka [42]

Solution:

(x² + x – 12)(x² + 10x + 25)
=> (x⁴ + 10x³ + 25x²) + (x³ + 10x² + 25x) + (-12x² - 120x - 300)
=> x⁴ + 10x³ + 25x² + x³ + 10x² + 25x - 12x² - 120x - 300
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The coefficient of x is -95.

6 0

2 years ago

Read 2 more answers

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murzikaleks [220]

Answer:

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Step-by-step explanation:

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3 years ago

You roll a 6-sided die.

Lerok [7]

Answer:

$\huge\boxed{\text{P(not factor of 35) = } \frac{2}{3}}$

Step-by-step explanation:

We can use basic probability to find the probability that this roll is not a factor of 35.

First off, we know that with a six sided die there are 6 possible things we can roll.

1, 2, 3, 4, 5, or 6

Now, what are the factors of 35? The factors of 35 will be any whole number that can be multiplied by another whole number to get 35.

We know $1 \cdot 35 = 35$ , so two factors are 1 and 35.
We know $5 \cdot 7 = 35$ , so two factors are 5 and 7.

Therefore, the factors of 35 are 1, 5, 7, 35.

Both 5 and 7 are inside the range of 1-6. So the probability of rolling a side that's a factor of 35 will be $\frac{2}{6} = \frac{1}{3}$ since there are two factors and 6 possible options.

This means, logically, there is a $\frac{4}{6} = \frac{2}{3}$ chance of not rolling a factor of 35.

Hope this helped!

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3 years ago

Which table shows no correlation?

Veseljchak [2.6K]

Instead of adding 6 three times, you can multiply 6 by 3 and get 18, the same answer.

Similarly,

6 + 6 + 6 + 6 + 6 + 6 + 6 = 6 × 7 = 42

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3 years ago

Which simplifications of the powers of i are correct? There may be more than one correct answer.

fredd [130]

$\bf i^2=-1\qquad\qquad i^3=-i\qquad \qquad i^4=1 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ i^{22}\implies i^{(4\cdot 5)+2}\implies i^{4\cdot 5}i^2\implies (i^4)^5 i^2\implies 1^5(-1)\implies -1~\dotfill \bigotimes \\\\\\ i^{11}\implies i^{(2\cdot 5)+1}\implies (i^2)^5 i\implies (-1)^5(i)\implies -i~\dotfill \checkmark$

$\bf i^{21}\implies i^{(4\cdot 5)+1}\implies (i^4)^5 i\implies 1^5(i)\implies i~\dotfill \checkmark \\\\\\ i^{12}\implies i^{3\cdot 4}\implies i^3 i^4\implies (-i)(1)\implies -i\dotfill \bigotimes \\\\\\ i^{20}\implies i^{4\cdot 5}\implies (i^4)^5\implies 1~\dotfill \checkmark \\\\\\ i^{26}\implies i^{(4\cdot 6)+2}\implies (i^4)^6 i^2\implies 1^6(-1)\implies -1\dotfill \checkmark \\\\\\ i^{27}\implies i^{(4\cdot 6)+3}\implies (i^4)^6 i^3 \implies 1^6(-i)\implies -i\dotfill \bigotimes$

6 0

3 years ago

Determine the value of the unknown 374=11(2n+8) ​

Determine the value of the unknown 374=11(2n+8)