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3 years ago

Find m<adc.please dhdhdhd

Mathematics

1 answer:

Alexus [3.1K]3 years ago

4 0

They both are complementary angles i.e their sum must equals 90°

4x+ 31 + 6x + 39 = 90
10x + 70 = 90
10x = 90-70
10x = 20
x = 2

we have to find angle ADC
just put the value of x in that expression for that angle.

angle ADC = 6x + 39 = 6 (2)+39 = 12 + 39 = 51°

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Dont really understand how to do this

bija089 [108]

Answers:

$t_{10} = -22 \ \text{ and } S_{10} = -85$

========================================================

Explanation:

$t_1 = \text{first term} = 5\\t_2 = \text{first term}-3 = t_1 - 3 = 5-3 = 2$

Note we subtract 3 off the previous term (t1) to get the next term (t2). Each new successive term is found this way

$t_3 = t_2 - 3 = 2-3 = -1\\t_4 = t_3 - 3 = -1-3 = -4$

and so on. This process may take a while to reach $t_{10}$

There's a shortcut. The nth term of any arithmetic sequence is

$t_n = t_1+d(n-1)$

We plug in $t_1 = 5 \text{ and } d = -3$ and simplify

$t_n = t_1+d(n-1)\\t_n = 5+(-3)(n-1)\\t_n = 5-3n+3\\t_n = -3n+8$

Then we can plug in various positive whole numbers for n to find the corresponding $t_n$ value. For example, plug in n = 2

$t_n = -3n+8\\t_2 = -3*2+8\\t_2 = -6+8\\t_2 = 2$

which matches with the second term we found earlier. And,

$tn = -3n+8\\t_{10} = -3*10+8\\t_{10} = -30+8\\t_{10} = \boldsymbol{-22} \ \textbf{ is the tenth term}$

---------------------

The notation $S_{10}$ refers to the sum of the first ten terms $t_1, t_2, \ldots, t_9, t_{10}$

We could use either the long way or the shortcut above to find all $t_1$ through $t_{10}$ . Then add those values up. Or we can take this shortcut below.

$Sn = \text{sum of the first n terms of an arithmetic sequence}\\S_n = (n/2)*(t_1+t_n)\\S_{10} = (10/2)*(t_1+t_{10})\\S_{10} = (10/2)*(5-22)\\S_{10} = 5*(-17)\\\boldsymbol{S_{10} = -85}$

The sum of the first ten terms is -85

-----------------------

As a check for $S_{10}$ , here are the first ten terms:

t1 = 5
t2 = 2
t3 = -1
t4 = -4
t5 = -7
t6 = -10
t7 = -13
t8 = -16
t9 = -19
t10 = -22

Then adding said terms gets us...

5 + 2 + (-1) + (-4) + (-7) + (-10) + (-13) + (-16) + (-19) + (-22) = -85

This confirms that $S_{10} = -85$ is correct.

6 0

2 years ago

Solve for y hdgkgsydkydutskgxtisit

Feliz [49]

You said X = (5y+1) / (y-2)

Multiply each side by (y-2):

X(y-2) = (5y+1)

Eliminate parentheses:

Xy - 2X = 5y + 1

Add 2X to each side:

Xy = 5y + 1 + 2X

Subtract 5y from each side:

(X-5)y = 1 + 2X

Divide each side by (X-5):

7 0

3 years ago

Read 2 more answers

3 exponet 8×4+9÷1×56+57

nika2105 [10]

You would use PEMDAS

But since any number divided by 1 is the number by which it is divided by then you can eliminate that. Now your problem looks like this:
8✖️4➕9✖️56➕57

Since there are no parentheses or exponents then you would multiply.
8✖️4= 32
32➕9✖️56➕57

Then multiply the other multiplication problem.
9✖️56= 504
32➕504➕57

Now you can add all of the numbers together
32➕504=536
536➕57=593

Your answer is 593

Hope this helps! :3

4 0

3 years ago

Read 2 more answers

For this item, complete the choice matrix by clicking the appropriate answer in each row.

Diano4ka-milaya [45]

Answer:

i cant see the link try reposting

Step-by-step explanation:

3 0

3 years ago

Which statement would be true if you evaluate the expression (560x70) ÷10

Marat540 [252]

Answer:

none

Step-by-step explanation:

No choice is correct.

The original expression has 560 x 70, the product of 560 and 70 inside the parentheses.

(560 x 70) ÷ 10 is 10 times smaller than 560 x 70

None of the choices show 560 x 70. They show 560 + 70 and 560 - 70.

Answer: none

8 0

3 years ago