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lakkis [162]
3 years ago
8

8) There are six boys and seven girls in a

Mathematics
1 answer:
kondaur [170]3 years ago
7 0

Answer:

i say dependent. i may be wrong

7/26

Step-by-step explanation:

6/13 times 7/12 which is 42/156 which is 14/52 which is also 7/26

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Decide whether or not the figures are similar. Explain why or why not.
AleksAgata [21]

Step-by-step explanation:

To tell if JKON and JKLM are similar, compare the ratios between corresponding sides.  For example:

JK / KO = 5/8

JK / KL = 5/22

The ratios aren't the same, so the shapes aren't similar.

3 0
3 years ago
Could someone help me solve this?
Andrew [12]
G has 2 local minimums, you can tell because there are 2 dips in the line before it goes of to infinity.
Both questions have the same answer so the answer to both would be
Local Min: (-2,-3), (3,0)
5 0
3 years ago
In what form is the following linear equation written? y-3=2/3(x-1)
lions [1.4K]
First we solve what we can solve.
<span>y</span>-3= 2/3<span>(</span>x-1)
We first multiply
<span>y</span>-3= 2/3 (x) - 2/3
Then we move the -3 and it becomes +3 on the other side
y= 2/3 (x) - 2/3 + 3
And we solve what we can to get our answer.
y= 2/3 (x) + 2 1/3
3 0
3 years ago
Read 2 more answers
What’s the answer to this question???????
saveliy_v [14]

Answer:

26

Step-by-step explanation:

if YZ bisects VW then VX = XW

if VX = 26 then XW = 26 also

5 0
3 years ago
An aircraft factory manufactures airplane engines. The unit cost (the cost in dollars to make each airplane engine) depends on t
Juliette [100K]

Answer:

Minimum unit cost = 5,858

Step-by-step explanation:

Given the function : C(x)=x^2−520x+73458

To find the minimum unit cost :

Take the derivative of C(x) with respect to x

dC/dx = 2x - 520

Set = 0

2x - 520

2x = 520

x = 260

To minimize unit cost, 260 engines must be produced

Hence, minimum unit cost will be :

C(x)=x^2−520x+73458

Put x = 260

C(260) = 260^2−520(260) + 73458

= 5,858

7 0
3 years ago
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