Answer:
Step-by-step explanation:
we know that
The perimeter of the rectangular lot is
----> equation A
where
AB is the length
BC is the width
we have
---> equation B
----> equation C
substitute equation B and equation C in equation A
solve for BC
<em>Find the value of AB</em>
If the whole diameter of sphere is 6 inch(means radius is 3 inch) & thickness of material is 1 inch, so the radius of the hollow part should be 2 inch (3-1=2)
The total volume of the ball will be;
= Total volume - Volume of hollow part
= 4/3πr³ - 4/3πr³
= 4/3 × 3.14 × (3)³ - 4/3×3.14×(2)³
= 4 × 3.14 × 9 - 4/3 × 3.14 × 8
= 113.04 - 33.52
= 79.52
If the density of the material is 3.25 g/in3, then the density of 79.52 inch³ should be;
= 79.52 × 3.25
= 258.44 g
Now, if there are 8 spheres in one box, the weight if box will be;
= 258.44 × 8
= 2,067.52 g
_____________________________
Ahh! Finally done with this, if you have any doubt just do ask me :)
1/4 is equal to 2/8.
2/8+1/8=3/8
Carla used 3/8 of the ribbon in all. So, 5/8 of the ribbon is left.
I hope this helps :)
Answer:
r=−1/5
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
5(r−10)=−51
(5)(r)+(5)(−10)=−51(Distribute)
5r+−50=−51
5r−50=−51
Step 2: Add 50 to both sides.
5r−50+50=−51+50
5r=−1Step 3: Divide both sides by 5.
5r/5=−1/5
r=−1/5
Answer:
40/6= 6.6667(20/3)
Step-by-step explanation:
I divided the number of days into 6.
