Set up an algebraic equation: b=cost of ball
1.10=1+b+b
1.10=1+2b
subtract 1 from both sides
.10=2b
divide by 2 on both sides
ball=5 cents
Answer:
Ben has mixed up the digit for millions and hundred thousands: he wrote 5 in the place for millions and 6 in the place for hundred thousands, but it should be the other way. I think that he should exchange those two digits in the faulty report.
Answer:
Minimum = 10
Q1 (quartile 1) = 14.5
Medium = 16
Q3 (quartile 3) = 17
Maximum = 18
Step-by-step explanation:
You just arrange the numbers in from smallest to greatest (even if some of them repeat). Then, look for the maximum and minimum. Get the median by having the same numbers left from both sides until reaching the median. The same holds for the quartiles (if you have for example two numbers for the quartile, as in this case 14 and 15, add the up and divide them by 2, in this case 14.5.
Tell me if I'm correct please
Answer:
3-3x/8
Step-by-step explanation:

First, I would multiply the last two fractions because they're smaller and easier to work with:

Now that we've simplified it, we could multiply these terms and simplify. An easier method, however, would be to cancel out any common factors among the numerators and denominators before multiplying:

We can now multiply these terms:

The <span>product of 8/15, 6/5, and 1/3 is B, 16/75.</span>