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8_murik_8 [283]
3 years ago
5

A phone company used to charge $30 per month plus $0.50 per text message for phone service. However, the company did not charge

a customer more than $80 per month regardless of how many text messages they sent.
The inequality that represented a customer's cost after x text messages was 80≥0.50x+30.

Which answer choice correctly analyzes this scenario?

For the inequality to be true, the value of x needs to be negative. Since x represents the number of text messages sent, there is no solution for this scenario.

The solution 100≥x means that, for the bill to equal $80, a customer can send no more than 100 text messages per month.

For the inequality to be true, the value of x needs to be less than 1. Since x represents the number of text messages sent, there is no solution for this scenario.

While x represents the number of text messages sent, the company did not charge more than $80 per month, so a customer could send unlimited text messages for $80 per month.
Mathematics
1 answer:
storchak [24]3 years ago
3 0

I would say the last one


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Savatey [412]
3x-52=2x+2 (v.o.a)
3x-2x=2+52
x=54
6 0
3 years ago
The braking distance, in feet of a car a Travling at v miles per hour is given.
irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

  • The braking distance at 25 mph, is approximately <u>63.7 ft.</u>
  • The braking distance at 55 mph,  is approximately <u>298.35 ft.</u>
  • The braking distance at 85 mph,  is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945  ft.s

D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

450 = 2.6 + \dfrac{v^2}{22}

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

8 0
2 years ago
Select the equation in slope-intercept form that is equivalent to: 4x + 3y = 12
sattari [20]

Answer:

y = -4/3x +4

Step-by-step explanation:

y= mx+b

solve for y.

4x+3y=12

Step 1: Add -4x to both sides.

4x+3y+−4x=12+−4x

3y=−4x+12

Step 2: Divide both sides by 3.

Let's solve for y.

4x+3y=12

Step 1: Add -4x to both sides.

4x+3y+−4x=12+−4x

3y=−4x+12

Step 2: Divide both sides by 3.

3y / 3 =-4x +12 /3

y = -4/3x +4

hopes this helps you out

5 0
3 years ago
At the grocery store 1/5 of the groceries are produce. Of the produce 2/3 is vegetables. What fraction of the groceries in the g
netineya [11]
If you have 1/5 and 2/3, you need a common denominator to even do anything. So three and five both go into 15, so then you do 2 times 5, cause 3 times 5 is 15. And 1 times 3, cause 3 times 5 is 15. So you end up with 3/15 as produce, and 10/15 as vegetables. So, then you divide the fractions, 1/5 divided by 10/15, which is the same as 1/5 times 15/10. So your answer is 3/10 of the produce is vegetables.
8 0
3 years ago
No links, ty &lt;3
levacccp [35]

Answer:

sAy yOu aRe mY bAkA

Step-by-step explanation:

ty for the points <3

4 0
3 years ago
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