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Eddi Din [679]
3 years ago
12

I Really Need Help With This One Can Some One Plz Help Me?

Mathematics
1 answer:
Lapatulllka [165]3 years ago
4 0
1.6²=1.6 times 1.6=2.56
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Rewrite in mathematical language. Every negative integer J is less than or equal to its inverse.
Luda [366]

Answer:

-J \leq J

Step-by-step explanation:

Given

Negative integer J

Required

Represent as an inequality of its inverse

The question didn't state if it's additive inverse or multiplicative inverse;

<em>Since the question has to do with negation, I'll assume it's an additive inverse</em>

<em></em>

The inverse of -J is +J

To represent as an inequality (less than or equal), we have:

-J \leq +J

Solving further, it gives

-J \leq J

3 0
3 years ago
Which expression is equivalent to ^4sqrt6/^3sqrt2?
BigorU [14]

\dfrac{\sqrt[4]6}{\sqrt[3]2}=6^\frac{1}{4}:2^\frac{1}{3}=6^\frac{1\cdot3}{4\cdot3}:2^{\frac{1\cdot4}{3\cdot4}}=6^\frac{3}{12}:2^\frac{4}{12}=(6^3)^\frac{1}{12}:(2^4)^\frac{1}{12}\\\\=216^\frac{1}{12}:16^\frac{1}{12}=(216:16)^\frac{1}{12}=\sqrt[12]{\dfrac{216}{16}}=\sqrt[12]{\dfrac{27}{2}}\\\\\text{Answer:}\ 1)\ \sqrt[12]{\dfrac{27}{2}}

4 0
2 years ago
Read 2 more answers
Solve quadratic equation x²-8x-1=0 by formula method​
Alex_Xolod [135]

Answer:

x²-8x-1=0

comparing above equation with ax²+bx+c=0

a=1

b=-8

c=-1

x=

x =  \frac{ - b +  -  \sqrt{ {b}^{2} - 4ac } }{2a}

=(--8+-√(64-4×1×-1)/2×1

=8+-√(64+4)/2

taking positive

x=(8+√68)/2=2(4+√17)/2=4+√17

taking negative

x=(8-√68)/2=2(4-√17)/2=4-√17

6 0
2 years ago
Read 2 more answers
Lin uses an app to graph the charge on her phone.
exis [7]

Answer:

  • See below

Step-by-step explanation:

<u>Use the graph to answer the following questions:</u>

When did she start using her phone?

  • At 2 afternoon

When did she start charging her phone?

  • At 8 afternoon

While she was using her phone, at what rate was Lin’s phone battery dying?

<u>From 100% to 40% between 2PM and 4 PM:</u>

  • (100 - 40)/(4 - 2) = 60/2 = 30% per hour
8 0
2 years ago
Read 2 more answers
Solve:<br>i)x+y=5<br>ii)x-y=3<br>iii)2x+y=7<br>iv)3x-2y=0​
Ulleksa [173]

Answer:

I) X+Y

when X=0

0+y=5

Y=5

When Y=0

X+0=5

X=5

(X,y)=(5,5)

(ii) X-Y=3

When X=0

0-Y=3

Y=-3

When Y=0

X-0=3

X=3

(X,Y)=(3,3(

(III) 2x+Y=7

when X=0

0+Y=7

Y=7

when Y=0

2x+0=7

2x=7

X=7/2 or 3.5

(X,Y)=(3.5,7)

(Iv)

3X-2Y=0

when X=0

0-2Y=0

-2Y=0

Y=0

When Y=0

3x-0=0

3X=0

X=0

(X,Y)=(0,0)

5 0
1 year ago
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