The answer to the question is d
Answer:
-1
because you are adding up to 0 to get back to the positive.
Here is a picture of each.
Here are the definitions of each:
1. Equilateral- this triangle has side lengths that are all the same (congruent).
2. Isosceles-this triangle has exactly 2 sides that are the same length(congruent).
3. Scalene- this triangle has no sides that are the same length.
Question 1
probability between 2.8 and 3.3
The graph of the normal distribution is shown in the diagram below. We first need to standardise the value of X=2.8 and value X=3.3. Standardising X is just another word for finding z-score
z-score for X = 2.8
(the negative answer shows the position of X = 2.8 on the left of mean which has z-score of 0)
z-score for X = 3.3
The probability of the value between z=-0.73 and z=0.49 is given by
P(Z<0.49) - P(Z<-0.73)
P(Z<0.49) = 0.9879
P(Z< -0.73) = 0.2327 (if you only have z-table that read to the left of positive value z, read the value of Z<0.73 then subtract answer from one)
A screenshot of z-table that allows reading of negative value is shown on the second diagram
P(Z<0.49) - P(Z<-0.73) = 0.9879 - 0.2327 = 0.7552 = 75.52%
Question 2
Probability between X=2.11 and X=3.5
z-score for X=2.11
z-score for X=3.5
the probability of P(Z<-2.41) < z < P(Z<0.98) is given by
P(Z<0.98) - P(Z<-2.41) = 0.8365 - 0.0080 = 0.8285 = 82.85%
Question 3
Probability less than X=2.96
z-score of X=2.96
P(Z<-0.34) = 0.3669 = 36.69%
Question 4
Probability more than X=3.4
P(Z>0.73) = 1 - P(Z<0.73) = 1-0.7673=0.2327 = 23.27%
Answer:
y-9 = -1/12(x-8)
Step-by-step explanation:
To write an equation of a line perpendicular to the graph of y = 12x-3 and passing through the point, we will follow the following steps.
The standard form of point-slope form of the equation of a line is given as
y − y1 = m(x − x1),
m is the slope of the unknown line
(x1, y1) is a point on the line.
Step 1: We need to calculate the slope of the known line first,
Given y = 12x-3
from the equation, m = 12 on comparison.
Step 2: get the slope of the unknown line. since the line given is perpendicular to the line y = 12x - 3, the product of their slope will be -1 i.e Mm = -1
M = -1/m
M is the slope of the unknown line
M = -1/12
Step 3: We will substitute M = -1/12 and the point (8, 9) into the point-slope form of the equation of a line i.e y − y1 = M(x − x1),
M = -1/12, x1 = 8 and y1 = 9
y-9 = -1/12(x-8)