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Olegator [25]
3 years ago
14

PLEASE I NEED HELP RN use the elimination method to solve. -7x+y=-19 -2x+3y=-19

Mathematics
1 answer:
-BARSIC- [3]3 years ago
8 0

Answer:

  (x, y) = (2, -5)

Step-by-step explanation:

The coefficient of y in the second equation is an integer multiple of the coefficient in the first equation, so it is convenient to eliminate y. Subtracting 3 times the first equation from the second, we have ...

  (-2x +3y) -3(-7x +y) = (-19) -3(-19)

  -2x +3y +21x -3y = -19 +57 . . . . . . . eliminate parentheses

  19x = 38 . . . . . . . . . simplify

  x = 2 . . . . . . . divide by 19

  -7(2) +y = -19 . . . . . substitute for x in the first equation

  y = -5 . . . . . . add 14

The solution is (x, y) = (2, -5).

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4 0
3 years ago
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Two construction contracts are to be randomly assigned to one or more of three firms: I, II, and III. Any firm may receive both
vichka [17]

Answer:

The owner's total profit is $120,000.

Step-by-step explanation:

Assume that:

<em>X</em>₁ = contract is assigned to firm 1

<em>X</em>₂ = contract is assigned to firm 2

The sample space for assigning the two contracts is:

S = {(I, I), (I, II), (I, III), (II, I), (II, II), (II, III), (III, I), (III, II) and (III, III)}

There are total of 9 possible combinations.

So, the probability of selecting any of the combination is, 1/9.

Compute the probability distribution of <em>X</em>₁ and <em>X</em>₂ as follows:

<em>X</em>₁      P (<em>X</em>₁)                      <em>X</em>₂        P (<em>X</em>₂)

0        4/9                        0           4/9

1         4/9                        1            4/9

2         1/9                        2           1/9

Compute the expected values of <em>X</em>₁ and <em>X</em>₂ as follows:

E(X_{1})=\sum X_{1}\cdot P(X_{1})\\\\=(0\times\frac{4}{9})+(1\times\frac{4}{9})+(2\times\frac{1}{9})\\\\=\frac{6}{9}\\\\=\frac{2}{3}               E(X_{2})=\sum X_{2}\cdot P(X_{2})\\\\=(0\times\frac{4}{9})+(1\times\frac{4}{9})+(2\times\frac{1}{9})\\\\=\frac{6}{9}\\\\=\frac{2}{3}

It is provided that each contract will yield a profit of $90,000.

Compute the owner's total profit as follows:

\text{Total Profit}=\text{Profit}\times [E(X_{1})+E(X_{2})]

                   =90000\times[\frac{2}{3}+\frac{2}{3}]\\\\=120000

Thus, the owner's total profit is $120,000.

7 0
3 years ago
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Tju [1.3M]

Answer:

Step-by-step explanation:

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$8.99+$0.4495=$9.4395

4 0
3 years ago
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