Answer:
<u>b(n) = -11 + (n-1)*8</u>
<u></u>
Step-by-step explanation:
Let n be the sequence number, with n=1 the first number b(1) -11
The sequence changes by +8 each step.
<u><em>b(1)</em></u><em> -11</em> + 8 = -3
<u><em>b(2)</em></u><em> -3</em> + 8 = 5
<u><em>b(3)</em></u> <em> 5 </em> + 8 = 13
<u><em>b(4)</em></u><em> </em> <em>13</em>
b(1) = -11
b(2) = -3. or b(1) + 1*8
b(3) = 5, or b(1) + 2*8
b(4) = 13, or b(1) + 3*8
We note that each step adds a multiple of 8 to the initial value of -11. This can be stated as (n-1)*8
The formula for this sequence would be b(n) = b(1) + (n-1)*8
<u>b(n) = -11 + (n-1)*8</u>
Check: Does n=3 return the value of 5?
b(n) = -11 + (n-1)*8
b(3) = -11 + ((3)-1)*8
b(3) = -11 + (2)*8
b(3) = -11 + 16
b(3) = 5 <u><em>YES</em></u>
Let x represent the number.
.. x^2 +x = 2
.. x^2 +x +1/4 = 9/4 . . . . add 1/4 to complete the square
.. x +1/2 = ±3/2 . . . . . . . .square root
.. x = -2, 1
Numbers meeting that requirement are -2 and 1.
Number of white chips = 4
Number of black chips = 6
Total number of chips = 4 + 6 = 10
Choosing the first white chip:
p(white chip) = 4/10 = 2/5
Now the numbers are:
Number of white chips = 3
Number of black chips = 6
Total number of chips = 3 + 6 =
Choosing the second white chip:
p(white chip) = 3/9 = 1/3
p(white chip followed by white chip) = 2/5 * 1/3 = 2/15
Answer:
total area = 615 sq. in.
Step-by-step explanation:
There are 4 triangles that make up the lateral area. The base of each triangle is 60/4 = 15 in. and the height of each triangle is 13 in. So, the area of one triangle = .5bh = .5(15)(13) = 97.5. The lateral area = 4(97.5) = 390. The area of the square base is 15(15) = 225. The total area = 390 + 225 = 615 sq. in.
Answer:
D
Step-by-step explanation:
y>-3x+1 Negative slope
y<u><</u>x+2 Positive slope
< or > have dotted line
<u><</u> or <u>></u> have a solid line
> or <u>></u> means solutions are above the line
< or <u><</u> means solutions are below the line
The one with negative slope has a dotted line and solutions above it.
The one with positive slope has a solid line and solutions below it.
