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Dima020 [189]
4 years ago
13

Find the product. -1/4 times 1/3

Mathematics
2 answers:
SpyIntel [72]4 years ago
7 0

Answer:

-1/4 x 1/3

-1/12

maw [93]4 years ago
5 0

Answer:

o.83

Step-by-step explanation:

nebbehehdhhdb d nfjfjf

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Express 245 as a product of its prime factors
antoniya [11.8K]
245= 5*7*7 :) so 5 and 7 are prime factors of 245 :)
7 0
3 years ago
Use matrices to solve the system of equations if possible. Use Gaussian elimination with back substitution or gauss Jordan elimi
CaHeK987 [17]

In matrix form, the system is given by

\begin{bmatrix} -1 & 1 & -1 \\ 2 & -1 & 1 \\ 3 & 2 & 1 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} -20 \\ 29 \\ 29 \end{bmatrix}

I'll use G-J elimination. Consider the augmented matrix

\left[ \begin{array}{ccc|c} -1 & 1 & -1 & -20 \\ 2 & -1 & 1 & 29 \\ 3 & 2 & 1 & 29 \end{array} \right]

• Multiply through row 1 by -1.

\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 2 & -1 & 1 & 29 \\ 3 & 2 & 1 & 29 \end{array} \right]

• Eliminate the entries in the first column of the second and third rows. Combine -2 (row 1) with row 2, and -3 (row 1) with row 3.

\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 5 & -2 & -31 \end{array} \right]

• Eliminate the entry in the second column of the third row. Combine -5 (row 2) with row 3.

\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 3 & 24 \end{array} \right]

• Multiply row 3 by 1/3.

\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 1 & 8 \end{array} \right]

• Eliminate the entry in the third column of the second row. Combine row 2 with row 3.

\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & 0 & -3 \\ 0 & 0 & 1 & 8 \end{array} \right]

• Eliminate the entries in the second and third columns of the first row. Combine row 1 with row 2 and -1 (row 3).

\left[ \begin{array}{ccc|c} 1 & 0 & 0 & 9 \\ 0 & 1 & 0 & -3 \\ 0 & 0 & 1 & 8 \end{array} \right]

Then the solution to the system is

\boxed{x=9, y=-3, z=8}

If you want to use G elimination and substitution, you'd stop at the step with the augmented matrix

\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 1 & 8 \end{array} \right]

The third row tells us that z=8. Then in the second row,

y-z = -11 \implies y=-11 + 8 = -3

and in the first row,

x-y+z=20 \implies x=20 + (-3) - 8 = 9

5 0
2 years ago
Which of the following is not a function?
neonofarm [45]

Answer:

D......................

6 0
3 years ago
Simplify the expression:<br> 10q–3q+2q2+3
saw5 [17]
If the 2q is raised to the second power the answer is 2q^2+7q+3
4 0
3 years ago
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is 0.75 less or greater than 7 over 8                                                                                           
Oksanka [162]
0.75 is 3/4 or 6/8, which is less than 7/8
4 0
4 years ago
Read 2 more answers
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