Answer:
Frank
Step-by-step explanation:
First let's start by calculating the speed of each runner.
Let's use feet per second
Frank's speed is already given in feet per second: 14 feet/second
We are given that Jake runs 382 feet in 38 seconds. To bring this down to feet/second we need to divide both numbers by 38.
382/38=10.05 feet/second (about)
We are given that Will runs 1 mile in 394 seconds. 1 mile is equivalent to 5280 feet. Now we divide both numbers by 394 to bring it down to feet/second.
5280/394=13.401 feet/second (about)
We are given that Ron runs 555 feet in 1 minute. 1 minute is equivalent to 60 seconds. Now we divide both numbers by 60 to bring it down to feet/second.
555/60=9.25 feet/second
After comparing all the speeds, we can conclude that Frank runs the fastest
Answer: 1 year = 1200
Y x 1200 = The visitors
(Y= Years/time)
Step-by-step explanation:
Let :
T = Theresa age
H = her brother
We know :
T = H - 14
T + H = 35
Substitute T
H -14 + H = 35
2H - 14 = 35
2H = 49
H = 49/2 = 24.5
Since we know H = 24.5 we then can substitute it to either equation.
T = H - 14
T = 24.5 - 14
T = 10.5
Theresa is 10.5 years old
Her brother is 24.5 years old
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:
And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
