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melamori03 [73]
3 years ago
7

If Fx) and G(X) are inverse functions, which statement must be true?

Mathematics
1 answer:
lawyer [7]3 years ago
8 0

Answer: F(G(x))=x

Step-by-step explanation:

I just took the test and I got it right!

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Sophia spent $27.16 on four sandwiches. If each sandwich cost the same amount, how much does one sandwich cost?
HACTEHA [7]

Answer:

6.79

Step-by-step explanation:

you just divide 27.16 (the cost) by 4 (how many sandwiches were purchased)

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Triangles H J K and L M N are shown. The triangles have identical side lengths and angle measures. Triangle H J K is slightly lo
Hitman42 [59]

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The answer is b : translate K to N and reflect across the line containing JK

Step-by-step explanation:

I just took the quiz

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3 years ago
Which model is shaded to represent the product Two-thirds times one-fourth?
Alinara [238K]

Answer:

12

Step-by-step explanation:

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7 0
3 years ago
How do you divide a whole number by a fraction​
lord [1]

Answer:Multiply the denominator on the bottom of the fraction by the whole number you are dividing by.

To divide a fraction by a whole number, multiply the bottom of the fraction by this whole number.

The denominator on the bottom of the fraction is 7.

We will multiply 7 by 2.

7 × 2 = 14 and so, 6 / 7 ÷ 2 = 6 / 14 .

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95
Virty [35]

Answer:

L(x)=1+\dfrac{1}{3}x

\sqrt[3]{0.95} \approx 0.9833

\sqrt[3]{1.1} \approx 1.0333

Step-by-step explanation:

Given the function: g(x)=\sqrt[3]{1+x}

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial,L(x)=f(a)+f'(a)(x-a)

a=0

g(0)=\sqrt[3]{1+0}=1

g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}

Therefore:

L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x

(b)\sqrt[3]{0.95}= \sqrt[3]{1-0.05}

When x = - 0.05

L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833

\sqrt[3]{0.95} \approx 0.9833

(c)

(b)\sqrt[3]{1.1}= \sqrt[3]{1+0.1}

When x = 0.1

L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333

\sqrt[3]{1.1} \approx 1.0333

7 0
3 years ago
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