The net force on the cart is 100 N in the direction of its motion, so by Newton's second law we can find the acceleration <em>a</em> applied to it:
100 N = (50 kg) <em>a</em>
<em>a</em> = (100 N) / (50 kg)
<em>a</em> = 2 m/s²
The cart starts at rest and travels a distance of 10 m, so that its final velocity <em>v</em> satisfies
<em>v</em> ² - 0² = 2 (2 m/s²) (10 m)
<em>v</em> ²= 40 m²/s²
and so the cart ends up with kinetic energy
KE = 1/2 <em>m</em> <em>v</em> ² = 1/2 (50 kg) (40 m²/s²) = 1000 J
The charge on the particle is 5.6 × 10⁻¹¹ C.
<h3>Calculation:</h3>
The magnitude of an electric field produced by a charge is given by:
E = q/ 4πε₀r²
where,
E = electric field
q = charge
r = distance
1/4πε₀ = 8.99 × 10⁹ Nm²/C²
Given,
E = 2.0 N/C
r = 50 cm = 0.5 m
To find,
q =?
Put the values in the above equation:
E = q/ 4πε₀r²
q = E (4πε₀r²)
q = 2.0 × (0.50²)/ 8.99 × 10⁹
q = 5.6 × 10⁻¹¹ C
Therefore, the particle has a charge of 5.6 × 10⁻¹¹ C.
<h3>What is an electric field?</h3>
The physical field that surrounds each electric charge and acts to either attract or repel all other charges in the field is known as an electric field. Electric charges or magnetic fields with different amplitudes are the sources of electric fields.
I understand the question you are looking for is this:
A charged particle produces an electric field with a magnitude of 2.0 N/C at a point that is 50 cm away from the particle. What is the magnitude of the particle's charge?
Learn more about electric field here:
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C 82.4 N sorry man if i am wrong but don't even think about reporting my answer
Answer:


Explanation:
v = Final velocity
u = Initial velocity
a = Acceleration
t = Time
s = Displacement
Here the kinematic equations of motion are used

Time the car is at constant velocity is 39 s
Time the car is decelerating is 5 s
Total time the car is in motion is 
Distance traveled




The total displacement of the car is 
Average velocity is given by

The average velocity of the car is
.
To solve this problem we will apply the principles of energy conservation. On the one hand we have that the work done by the non-conservative force is equivalent to -30J while the work done by the conservative force is 50J.
This leads to the direct conclusion that the resulting energy is 20J.
The conservative force is linked to the movement caused by the sum of the two energies, therefore there is an increase in kinetic energy. The decrease in the mechanical energy of the system is directly due to the loss given by the non-conservative force, therefore there is a decrease in mechanical energy.
Therefore the correct answer is A. Kintetic energy increases and mechanical energy decreases.