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LenaWriter [7]
3 years ago
12

A fuel cell that is becoming very popular for cars runs on:

Physics
1 answer:
jok3333 [9.3K]3 years ago
7 0
It runs on Hydrogen gas.

Actually, using hydrogen as a fuel is not new. We used to use it on air vehicle like air balloon. But back then, we still cannot figure out how to safely use this because Hydrogen exlodes rather easily
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A horizontal force of 100 N is applied to move a 50-kg cart (initially at rest) across a 10 m level surface. What is the final k
OlgaM077 [116]

The net force on the cart is 100 N in the direction of its motion, so by Newton's second law we can find the acceleration <em>a</em> applied to it:

100 N = (50 kg) <em>a</em>

<em>a</em> = (100 N) / (50 kg)

<em>a</em> = 2 m/s²

The cart starts at rest and travels a distance of 10 m, so that its final velocity <em>v</em> satisfies

<em>v</em> ² - 0² = 2 (2 m/s²) (10 m)

<em>v</em> ²= 40 m²/s²

and so the cart ends up with kinetic energy

KE = 1/2 <em>m</em> <em>v</em> ² = 1/2 (50 kg) (40 m²/s²) = 1000 J

8 0
3 years ago
a charged partocle produces an electric field with a magnitude of 2.0 N/C at a point that is 50cm away from the particle
zheka24 [161]

The charge on the particle is 5.6 × 10⁻¹¹ C.

<h3>Calculation:</h3>

The magnitude of an electric field produced by a charge is given by:

                                                 E = q/ 4πε₀r²

where,

E = electric field

q = charge

r = distance

1/4πε₀ = 8.99 × 10⁹ Nm²/C²

Given,

E = 2.0 N/C

r = 50 cm = 0.5 m

To find,

q =?

Put the values in the above equation:

E = q/ 4πε₀r²

q = E (4πε₀r²)

q = 2.0 × (0.50²)/ 8.99 × 10⁹

q = 5.6 × 10⁻¹¹ C

Therefore, the particle has a charge of 5.6 × 10⁻¹¹ C.

<h3>What is an electric field?</h3>

The physical field that surrounds each electric charge and acts to either attract or repel all other charges in the field is known as an electric field. Electric charges or magnetic fields with different amplitudes are the sources of electric fields.

I understand the question you are looking for is this:

A charged particle produces an electric field with a magnitude of 2.0 N/C at a point that is 50 cm away from the particle. What is the magnitude of the particle's charge?

Learn more about electric field here:

brainly.com/question/14857134

#SPJ4

4 0
2 years ago
Please help me with this Physics question?
Leno4ka [110]

C 82.4 N sorry man if i am wrong but don't even think about reporting my answer

6 0
3 years ago
A self-driving car traveling along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a spe
Rasek [7]

Answer:

56.5\ \text{s}

21.13\ \text{m/s}

Explanation:

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

s = Displacement

Here the kinematic equations of motion are used

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{25-0}{2}\\\Rightarrow t=12.5\ \text{s}

Time the car is at constant velocity is 39 s

Time the car is decelerating is 5 s

Total time the car is in motion is 12.5+39+5=56.5\ \text{s}

Distance traveled

v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{25^2-0}{2\times 2}\\\Rightarrow s=156.25\ \text{m}

s=vt\\\Rightarrow s=25\times 39\\\Rightarrow s=975\ \text{m}

v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{0-25}{5}\\\Rightarrow a=-5\ \text{m/s}^2

s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0-25^2}{2\times -5}\\\Rightarrow s=62.5\ \text{m}

The total displacement of the car is 156.25+975+62.5=1193.75\ \text{m}

Average velocity is given by

\dfrac{\text{Total displacement}}{\text{Total time}}=\dfrac{1193.75}{56.5}=21.13\ \text{m/s}

The average velocity of the car is 21.13\ \text{m/s}.

6 0
3 years ago
As an object moves from point A to point B only two forces act onit: one force is nonconservative and does -30 J of work, the ot
Romashka-Z-Leto [24]

To solve this problem we will apply the principles of energy conservation. On the one hand we have that the work done by the non-conservative force is equivalent to -30J while the work done by the conservative force is 50J.

This leads to the direct conclusion that the resulting energy is 20J.

The conservative force is linked to the movement caused by the sum of the two energies, therefore there is an increase in kinetic energy. The decrease in the mechanical energy of the system is directly due to the loss given by the non-conservative force, therefore there is a decrease in mechanical energy.

Therefore the correct answer is A. Kintetic energy increases and mechanical energy decreases.

7 0
3 years ago
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