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LenaWriter [7]
3 years ago
12

A fuel cell that is becoming very popular for cars runs on:

Physics
1 answer:
jok3333 [9.3K]3 years ago
7 0
It runs on Hydrogen gas.

Actually, using hydrogen as a fuel is not new. We used to use it on air vehicle like air balloon. But back then, we still cannot figure out how to safely use this because Hydrogen exlodes rather easily
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Which best describes the direction of heat?
Gekata [30.6K]

Answer:

MRCORRECT has answered the question

Explanation:

According to second law of thermodynamic,heat flows from higher to lower temperature region. Heat is the transfer of energy from an object at higher temperature to an object at a lower temperature. so energy flows from warmer to colder objects

6 0
3 years ago
Micah knows that a car had a change in velocity of 15 m/s. What does micah need to determine acceleration.
katrin2010 [14]
The time component is needed. The acceleration is the change of velocity divided by the time in when this change of velocity happens.
4 0
3 years ago
Read 2 more answers
Choose the answer choice that BEST completes the following sentence. About four million tons of __________________ are converted
yaroslaw [1]

Answer:

<em>About four million tons of </em><em><u>matter</u></em><em> are converted to energy in the Sun’s core every second</em>

Explanation:

<u>The Sun </u>

It's estimated that The Sun fuses near 600 million tons (6.10^9\ kg) of hydrogen into helium every second. As a result, 4 million tons of matter are converted to energy every second according to Einstein's equation E=mc^2

4 0
4 years ago
The type of energy that depends on position is called
attashe74 [19]
The type of energy that depends on position is called
kinetic energy
5 0
3 years ago
Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.320 mm wide. The diffraction pattern is observed
DanielleElmas [232]

Answer:

W = 10.28\ mm

Explanation:

Given,

Red light wavelength = 633 nm

width of slit = 0.320 mm

distance,d = 2.60 m

Condition of first maximum

a sin \theta_1 = m\lambda

\theta_1 =sin^{-1}(\dfrac{m\lambda}{a})

m = 1

\theta_1 =sin^{-1}(\dfrac{633\times 10^{-9}}{0.32\times 10^{-3}})

\theta_1 = 0.1133^\circ

Width of the first minima

y_1 = L tan \theta_1

y_1 = 2.60\times tan( 0.11331)

y_1 = 5.14 \ mm

Now, width of the central region

W = 2 y_1

W = 2\times 5.14

W = 10.28\ mm

8 0
3 years ago
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