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Dovator [93]
3 years ago
15

You walk forward at 1.5 m/s for 8s. Your friend decides to walk faster and starts out at 2.0 m/s for the first 4 s. Then she slo

ws down and walks forward at 1.0 m/s for the next 4s. Make a distance-time graph of your motion and your friend's motion. Who walked farther?

Physics
1 answer:
Troyanec [42]3 years ago
6 0
The first thing you should know is that the distance is equal to the speed per time.
 Therefore if You walk forward at 1.5 m / s for 8s
 d = 1.5t [0,8] s
 Your friend decides to walk faster and starts at 2.0 m / s for the first 4 s.
 d = 2t [0,4] s
 Then she slows down and walks forward at 1.0 m / s for the next 4s
 d = t + 4 [4,8] s
 Who walked farther?
 They both walked the same distance
 12 meters

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