Both, there are two different types of molecules to distinguish that
 
        
                    
             
        
        
        
Answer:
Answer is C
Explanation:
Let's say the pendulum starts swinging from its max height from the left. It then will go down and reach the equilibrium position, this will make it lose GPE while gaining KE (the loss in GPE = gain in KE). At the equilibrium position it has the max KE (max velocity) and minimum GPE. After passing the equilibrium it then starts to head up to the max height on the right, the pendulum gains GPE while losing KE and at the top will have minimum KE while having max GPE. Meaning throughout its joruney the total energy remains constant as
Total energy = KE + GPE
I have attached a simple diagram below, the y axis is the energy and x axis being the time (where t = 0 is the pendulum starting from max height left of the equilibrium). The green curve the the GPE and blue curve is KE. Red line shows that at all times the energy is constant.
 
        
             
        
        
        
Answer:
No
Explanation:
From the analogy of the problem we are made to know that "a man standing on the earth can exert the same force with his legs as when he is standing on the moon". 
  This force he is exerting is due to his weight. If he can have the same weight on the earth and moon, therefore: 
       weight  = mass x acceleration due gravity
His mass and acceleration due to gravity on both terrestrial bodies are the same. 
So, his jump height will be the same on earth and on the moon.
In summary, we have been shown that his mass and the acceleration due to gravity on both planets are the same, therefore, his weight will also be the same. His jump height will also be same. 
 
        
             
        
        
        
-- Gravity makes a falling object fall 9.8 m/s faster every second.
-- So, it reaches the speed of 30 m/s in (30/9.8) = 3.06 seconds after it's dropped.
-- The distance an object falls from rest is D = 1/2 (acceleration) (time)²
D = 1/2 (9.8 m/s²) (3.06 sec)²
D = (4.9 m/s²) (9.37 sec²)
<em>D = 45.8 meters</em>
Notice that we don't care how high the building is.  The problem works just as long as the object can reach 30 m/s before it hits the ground.  That  turns out to be anything higher than 45.8 meters for the drop . . . maybe something like 13 floors or more.
Now I'll go a little farther for you !  Writing the last paragraph made me a little curious and uncomfortable.  So I went and looked up the world's tallest buildings . . . and I found out that this problem could never happen !
The tallest building in the world now is the Burj Khalifa, in  Dubai.  It has 163 floors, and it's 828 meters high !  That's 2,717 feet.  It's gonna be a long time before there's a building that's 1125 meters tall, like this problem says.  That's close to 3700 feet . . . I've had flying lessons where I wasn't that far off the ground !
 
        
             
        
        
        
Conservation in this case means that it doesn't change. Momentum isn't created or destroyed, but it remains constant.