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3 years ago

I need help ASAP. This is for 15 points

Physics

1 answer:

kramer3 years ago

7 0

Answer:

Latitude :

runs: east to west

measures : distances north and south of the equator

Longitude :

runs : north to south

measures : the distance east or west of the Prime Meridian

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Light travels in a straight line at a constant speed of 3.0 x 10 8 m/s for 4.1

Over [174]

Answer:

Explanation:

As the velocity of light is constant so the acceleration of the light is equal to zero.

3 0

3 years ago

Think about your displacement at three different times throughout your day and compare it with e distance you traveled. (6 point

photoshop1234 [79]

Here, we are asked to calculate the total distance and displacement for three different times.

Before solving the question, first we have to understand the distance and displacement.

Displacement is the minimum distance travelled between two points. Hence, it is a vector quantity. On the other hand, the distance travelled is a scalar quantity.

The total displacement will be calculated by vector addition while total distance will follow algebraic addition.

Let us consider Ram travelled 3 km towards north from his home to office in 1 hour. The highway is straight. He reached at his office and saw that his office was closed. So, he came back. He stopped at shop for 2 minutes which was 2 km away from his office. Then he started his journey and reached him home.

Let his first distance travelled from home to office is $s_{1} =\ 3\ km$

Here, the displacement is also the same in magnitude with distance travelled and it is directed towards north.

The distance travelled by Ram from office to the shop $s_{2} =2\ km$

Here, the displacement is 2 km towards south.

The distance travelled by Ram from the shop to the office $s_{3} =\ 1 \ k m$

Here, the displacement is 1 km towards south.

Here, the total distance travelled $[s]\ =\ s_{1} +s_{2} +s_{3}$

$=3\ km+2\ km+1\ km$

$=6\ km$

Now we have to calculate the total displacement. Here, the total displacement is zero.

It is because the initial and final points of his journey is same.

5 0

3 years ago

A particular molecule has a small molecular mass of approximately 1000 daltons. What should be done to make this molecule more a

barxatty [35]

Answer:

Bind it to a large protein

Explanation:

An antigen is a molecule that binds to Ag-specific receptors, but cannot necessarily induce an immune response in the body by itself. Antigens are proteins , peptides (amino acid chains) and

polysaccharides (chains of monosaccharides/simple sugars) but

lipids and nucleic acids become antigens only when combined with proteins and polysaccharides. [4] In general, saccharides and lipids (as opposed to peptides) qualify as antigens but not as immunogens since they cannot elicit an immune response on their own. Furthermore, for a peptide to induce an immune response it must be a large enough size, thus binding to proteins

7 0

3 years ago

A submarine has a "crush depth" (that is, the depth at which

sergey [27]

Answer:

P =40.69 atm

Explanation:

We need to find the approximate pressure at a depth of 400 m.

It can be calculated as follows :

P = Patm + ρgh

Put all the values,

$P=1\ atm+1025 \times 9.81\times 400\times 9.8692\times 10^{-6}\ atm/Pa\\\\P=40.69\ atm$

So, the approximate pressure is equal to 40.69 atm.

3 0

3 years ago

It is easier to roll a stone up a sloping road than to lift it vertical upwards because.

kvasek [131]

Answer:

Because the force one needs to apply is reduced.

Explanation:

Work can be expressed in terms of force and distance as follows,

Work = Force × distance

To be more precise, the selection of these two parameters should be in a manner that the distance is what the line of action of the force traces.
It is obvious that for a given amount of work when one parameter is changed the other changes to counteract the change of the first one.
Imagine the situation shown in the attached figure. The amount of work that needs to be done during the lifting of the mass to a height of $\small h$ vertically is $E = mg\times h = mgh$ .
On the slope, however, one needs to push the object an $L$ distance up to get the object to that $h$ height ultimately.
The work he does on the slope is $mgh = F\times L$ and since $L > h$ , $F < mg$ .
The force that needs to be applied is less than that applied in the vertical lift. Hence it feels easier. #SPJ4

3 0

1 year ago