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Novosadov [1.4K]
3 years ago
15

What's another way to express the expression [4(17) + 3(25)] x 5?

Mathematics
1 answer:
Elis [28]3 years ago
5 0

Answer:

715

Step-by-step explanation:

[4(17) + 3(25)] x 5

(68+3*25)*5

(68+75)*5

143*5

175

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Given the circle with the diameter of 33 cm find the area of the circle
exis [7]

Answer:

51.81 cm^2

Step-by-step explanation:

Find The Half Of 33 which is 16.5

Use The Formula For Area

A= \pi x r^2

A= 3.14 x 16.5

A= 51.81 cm^2

3 0
3 years ago
Por favor responder a esta pregunta
ahrayia [7]
Por determinante:
5...1...1
1...0...1 = 0 --> se o determinante for igual a 0, os pontos estarão alinhados.
3...3...1

calculando: (5 x 0 x 1 + 1 x 1 x 3 + 1 x 3 x 1) - (1 x 0 x 3 + 1 x 1 x 1 + 3 x 1 x 5) = 
0 + 3 + 3 - 0 - 1 - 15 = 
6 - 1 - 15 = 
5 - 15 = - 10 --> como não deu zero, os pontos não estão alinhados.
4 0
3 years ago
Please Show Your Work!
timurjin [86]

Answer:

You have to have a Y and X axis line it may help. You can also time the few and yeah your smart you can do this i can help with more.

Step-by-step explanation:

I do this work. Thanks have a splendid life! Ask 4 me to solve more! Byes!

8 0
3 years ago
Evaluate the difference quotient for the given function. Simplify your answer.
nasty-shy [4]

I suppose you mean

f(x) = \dfrac{x+5}{x+1}

Then

f(3) = \dfrac{3+5}{3+1} = \dfrac84 = 2

and the difference quotient is

\dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5}{x+1}-2}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5-2(x+1)}{x+1}}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{-x+3}{(x+1)(x-3)} \\\\ \dfrac{f(x)-f(3)}{x-3} = \boxed{-\dfrac{x-3}{(x+1)(x-3)}}

If it's the case that <em>x</em> ≠ 3, then (<em>x</em> - 3)/(<em>x</em> - 3) reduces to 1, and you would be left with

\dfrac{f(x)-f(3)}{x-3}\bigg|_{x\neq3} = -\dfrac1{x+1}

4 0
2 years ago
todd earn $91.00 working for her uncle yesterday if he worked for 6.5 hours how much did he earn per hour
emmasim [6.3K]
Answer= 14 per hour
91/6.5
=14
Todd earn $14 per hour
3 0
3 years ago
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