Answer:

And replacing:

And the deviation:

And the distribution is given:

Step-by-step explanation:
For this case we have the following info given :

And the deviation would be 
For this case we select a sample size of n = 5 and the distirbution for the sample mean would be:

And replacing:

And the deviation:

And the distribution is given:

Answer:
[0.9 months, 32.69 months]
Step-by-step explanation:
The mean is
The standard deviation is
Now, we have to find two values a and b such that the area under the Normal curve with mean 16.8 and standard deviation 8.1092 between a and b equals <em>95% = 0.95
</em>
Using a spreadsheet we find these values are
a = 0.906
b = 32.694
<h3>(See picture)
</h3>
and our 95% confidence interval for the mean number of months elapsed since the last visit to a dentist for the population of students participating in the program rounded to two decimal places is
[0.9 months, 32.69 months]
Using a calculator can help. You get 0.625, or 5/8.
9.286
[To change to mixed number, count the number of digits after the decimal point. There are 3 digits, so the denominator will be 1000]

Then we simplify the fraction
(286 ÷ 2)/(1000÷2) = 143/500
Therefore,

1 penny = 0.005 ft
total amt of pennies = 1264/0.005 = 252800 pennies