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Kaylis [27]
3 years ago
15

PLEASE HELP!!

Mathematics
1 answer:
Stels [109]3 years ago
8 0

Answer:

the correct answer is B.-2/3



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masha68 [24]
Huh? What do you mean I don't understand
7 0
3 years ago
Read 2 more answers
What the questions are asking help ASAP please
Rudiy27

Answer:

Step-by-step explanation:

A scalar is a constant value that is multiplied throughout a matrix.

e.g.

In number 1 the set up would look like this

3 * \left[\begin{array}{ccc}3&-1&5\\2&1&-4\\-6&3&2\end{array}\right]

To solve this, you must distribute the 3 to each value within the matrix

The solution to #1 would be

M = \left[\begin{array}{ccc}9&-3&15\\6&3&-12\\-18&9&6\end{array}\right]

3 0
3 years ago
How to find components of a vector given magnitude and angle?
Zanzabum
<span>1. Find the magnitude and direction angle of the vector.
2. Find the component form of the vector given its magnitude and the angle it makes with the positive x-axis.
<span>3. Find the component form of the sum of two vectors with the given direction angles.</span></span>
3 0
3 years ago
Please Help!!!
vaieri [72.5K]

I DON'T UNDERSTAND MATH ANYMORE!!!!!!!!

7 0
3 years ago
I'm not sure where to start and how to differentiate this.
Mazyrski [523]
The picture is not clear. let me assume y = (x^4)ln(x^3)

product rule :
d f(x)g(x) = f(x) dg(x) + g(x) df(x)

dy/dx = (x^4)d[ln(x^3)/dx] + d[(x^4)/dx] ln(x^3)
= (x^4)d[ln(x^3)/dx] + 4(x^3) ln(x^3)

look at d[ln(x^3)/dx]
d[ln(x^3)/dx]
= d[ln(x^3)/dx][d(x^3)/d(x^3)]
= d[ln(x^3)/d(x^3)][d(x^3)/dx]
= [1/(x^3)][3x^2] = 3/x
... chain rule (in detail)

end up with
dy/dx = (x^4)[3/x] + 4(x^3) ln(x^3)
= x^3[3 + 4ln(x^3)]

5 0
3 years ago
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