Answer:

Step-by-step explanation:
![Volume\:of\:cube:V=a^{3} \:(a\:is\:the\:length\:of\:each\:edge)\\\Leftrightarrow a=\sqrt[3]{V} \Leftrightarrow a=\sqrt[3]{729} =9](https://tex.z-dn.net/?f=Volume%5C%3Aof%5C%3Acube%3AV%3Da%5E%7B3%7D%20%5C%3A%28a%5C%3Ais%5C%3Athe%5C%3Alength%5C%3Aof%5C%3Aeach%5C%3Aedge%29%5C%5C%5CLeftrightarrow%20a%3D%5Csqrt%5B3%5D%7BV%7D%20%5CLeftrightarrow%20a%3D%5Csqrt%5B3%5D%7B729%7D%20%3D9)
No sé lo siento esqje necesito mas puntos lol hahaha
Answer:
Step-by-step explanation:

Could you confirm to me that this is in fact the problem? Do not report. I will edit this answer once you answer my question.
You need Pythagorean theorem for this.
a² + b² = c², where c is the hypotheneus and a and b are the sides of the right triangle.
24² + x² = 26²
x² = 676-576
x = ±√100
x = 10 (-10 is rejected because length of triangle cannot be a negative number)