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3 years ago

Please help me ASAP!!

Mathematics

1 answer:

nydimaria [60]3 years ago

8 0

Answer:

(-4,4) (3,-4) is the answer

Step-by-step explanation:

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coldgirl [10]

Cos(x) = 32/40 = 0.8 ⇒ x ≈ 37°

6 0

4 years ago

An airplane cuts through the morning sky for every 1,000 feet that he climbs the outside temperature drops 20° f what is the rat

Oliga [24]

Given :

An airplane cuts through the morning sky for every 1,000 feet that he climbs the outside temperature drops 20° F.

To Find :

The rate of the temperature change in degrees Fahrenheit per foot.

Solution :

Let, rate of the temperature change in degrees Fahrenheit per foot is x.

So,

$x = \dfrac{20}{1000}\ ^oF/foot\\\\x = 0.02 ^oF/foot$

Therefore, rate of the temperature change in degrees Fahrenheit per foot is 0.02.

Hence, this is the required solution.

4 0

3 years ago

Please hurry its timed

vampirchik [111]

Answer:

-1

Step-by-step explanation:

yep its that okb

yaaaaay

7 0

3 years ago

Suppose you wanted to change the state’s constitution to require public financing for all campaigns. If you were relying on prof

Reil [10]

Answer: $1.5 millions

Step-by-step explanation:

Since the population is in millions and a million is like a fraction many millions.

Therefore, the minimum amount of money you could reasonably expect to spend in order to qualify for this amendment for the ballot is $1.5 millions

4 0

3 years ago

A population of 490 bacteria is introduced into a culture and grows in number according to the equation below, where t is measur

Lera25 [3.4K]

Answer:

Rate of growth of bacteria when t=2 is 3.09 bacteria/hour

Step-by-step explanation:

As equation is not given so considering the Equation of growth of bacteria as

$P=490(1+\frac{4t}{50+t^{2}})$

We have to find the rate at which population is growing. To do so differentiate above equation w.r.to 't'

$\frac{dP}{dt}=\frac{d}{dt}490(1+\frac{4t}{50+t^{2}})\\\\\frac{dP}{dt}=490(\frac{d}{dt}(1)+\frac{d}{dt}(\frac{4t}{50+t^{2}}))\\\\\frac{dP}{dt}=490(0+\frac{4(50+t^{2})-(4t)(2t)}{(50+t^{2})^{2}})\\\\\frac{dP}{dt}=490(\frac{200+4t^{2}-8t^{2}}{(50+t^{2})^{2}})\\\\\frac{dP}{dt}=490(\frac{4(50-t^{2})}{(50+t^{2})^{2}})\\\\at\,\,t=2hours\\\\\frac{dP}{dt}=490(\frac{4(50-(2)^{2})}{(50+(2)^{2})^{2}})\\\\\\\frac{dP}{dt}=490(\frac{4(50-4)}{(50+4)^{2}})\\\\=3.09$

Rate of growth of bacteria when t=2 is 3.09 bacteria/hour

8 0

3 years ago