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JulijaS [17]
3 years ago
5

Line AB has endpoints A(-4,5) and B(3,5). What is the x-coordinate of a point C such that B is the midpoint of line AC

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
7 0
Easy peasy

the midpoint between (x_1,y_1) and (x_2,y_2) is
(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})
just average them

so given that (3,5) is the midpoint of (-4,5) and (x,y)
(\frac{-4+x}{2},\frac{5+y}{2})=(3,5)
so by logic
\frac{-4+x}{2}=3 and \frac{5+y}{2}=5
times both sides by 2 for everybody
-4+x=6 and 5+y=10
add 4 to both sides for left one and minus 5 from both sides for right
x=10 and y=5

the coordinate of point C is (10,5)
the x coordinate is 10
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Show how to use the distributive property to simplify 4(5+x)
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Answer:

20+4x

Step-by-step explanation:

Distributive property is quite easy to learn... its just multiplication in an easier form to visualize once you're used to using it.

To first start this problem you want to use the number 4 in the expression 4(5+x). You then want to multiply 4 by both terms inside of the parentheses. So you would do both 4*5 and 4*x. You would then get 20+4x because 4*5=20 and 4*x is just put together as 4x.

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Zachary says that the equation 0 =-1/2 (x – 4)(x –
melomori [17]
<u><em>Answer:</em></u>
c = 4

<u><em>Explanation:</em></u>
The number of solutions for any equation is equal to the degree of the equation.

The given equation is a second degree equation which means that it has two solutions.

The only possible way for it to have one unique real solution is that the two <u>solutions are equal</u>

<u>This means that:</u>
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6 0
3 years ago
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Find the perimeter of a polygon with vertices at A(0, 1), B(4, 4), C(7, 0), D(3, -3), E(-4, -4). Round your answer to the neares
wlad13 [49]

It's interesting that areas from coordinates are much simpler than perimeters from coordinates.  It's almost like math is telling us area is more fundamental than length.

p = AB+BC+CD+DE+EA

We use the Pythagorean theorem, square root form, on all the sides.  We can skip a lot of the square roots because most of these are the hypotenuse of a 3/4/5 right triangle.

B-A=(4-0, 4-1)=(4,3) so length AB=5

C-B=(7-4,0-4)=(3,-4), so again  BC=5

D-C=(3-7, -3-0)=(-4,-3) so again CD=5

E-D=(-4-3, -4 - -3) = (-7, -1).  Ends our streak.  DE=√(7²+1²)=√50=5√2.

A-E=(0 - -4,1 - -4)=(4,5) so EA=√(4²+5²)=√41.

Three of five were 3/4/5.

p = 5+5+5+5√2+√41 = 15+5√2+√41

I hate to ruin a nice exact answer with an approximation.

p ≈ 28.474192049298324

Answer: 28.47, last choice

8 0
3 years ago
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