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avanturin [10]
3 years ago
14

Pleaseeeee help meee

Mathematics
1 answer:
blsea [12.9K]3 years ago
6 0
Best way to do problems like this put it in Tiger Solver Calculater off of Google. It will get it right everytime.
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What is the value of 12x^-3 y-1 for x=-1 and y=5<br> A.-12/5<br> B.-180<br> C.-60<br> D.-5/12
Mkey [24]

Expressions are mathematical statements represented with the variables

The value of 12x^-3 y-1 for x=-1 and y=5 is - 12/5

<h3>How to determine the value of the variable</h3>

The expression is given as:

12x^{-3} y^{-1}

When x = -1, the expression becomes

12 * -1^{-3} y^{-1}

Evaluate the exponent

- 12 y^{-1}

When y = 5, the expression becomes

- 12 * 5^{-1}

Evaluate the exponent

- 12/5

Hence, the value of 12x^-3 y-1 for x=-1 and y=5 is - 12/5

Read more about expressions at:

brainly.com/question/723406

5 0
3 years ago
Find r(t) if r'(t)=ti+e^tj+te^tk and r(0)=i+j+k
weeeeeb [17]
R(t) = integral of r'(t) = integral of ti + e^tj + te^tk = 1/2t^2i + e^tj + (te^t - e^t)k + c
r(0) = j - k + c = i + j + k
c = i + 2k
Therefore, r(t) = (1/2t^2 + 1)i + e^tj + (te^t - e^t + 2)k
6 0
4 years ago
Help please!!<br> 1. What is the value of n?<br> 2.What is the value of n?
lana66690 [7]

Using the intersecting chord theorem:

15 x 2 = 5 x n

Simplify:

30 = 5n

Divide both sides by 5:

n = 30/5

n = 6 m



8 x n+8 = 16 x n+2

Simplify:

8n +64 = 16n +32

Subtract 8n from both sides:

64 = 8n +32

Subtract 32 from both sides:

32 = 8n

Divide both sides by 8:

n = 32 /8

n = 4

4 0
4 years ago
Read 2 more answers
1. which number is a solution to the inequality?
katen-ka-za [31]
1.
8 < x(7 - x)

We can now substitute the given values to see which one satisfies the inequality.
8 < 2(7 - 2)
8 < 10
A is the correct answer.

2.
D.
This lists all of the factors of 24.
3 0
3 years ago
I suck at figuring out the radius of a circle :c<br> Can someone help please :(
kvv77 [185]

First question:

The line segment that is 40 ft long is a tangent to the circle, meaning it creates a right angle with the radius that intersects it.

Let r be the radius of the circle.

We have a right triangle where the legs are r and 40, and the hypotenuse is (20+r)

I'm hoping you remember the Pythagorean Theorem because this is going to be an important equation for this problem (and the next).

Let's use the dimensions of the right triangle and create a Pythagorean Theorem truth statement:

r^2+40^2=(20+r)^2

Simplify the right side so it's easier to solve

r^2+1600=400+40r+r^2

Subtract both sides by r²

1600=400+40r

Subtract both sides by 400

1200=40r

Divide both sides by 40

r=30

The value of r is 30, meaning the radius is 30 feet.

Second question:

Please look at the attached image, it would be too hard to try and describe this in words.

We have a right triangle where the legs have a length of 3.6 and half of the length of KL, which is 4.

The hypotenuse is the radius, x.

Use Pythagorean Theorem's to solve for x

3.6^2+4^2=x^2

Simplify

x^2=28.96

Use a calculator to take the square root of 28.96

x=5.3814...

The image is not complete so I can't see how I have to round it, so here are a few different ways this could be rounded:

  • To the nearest tenths: x=5.4
  • To the nearest hundredths: x=5.38
  • To the nearest thousandths: x=5.381

Answerer's Note:

I'm so sorry this took so long to answer. Let me know if you need any clarifications, thanks!

~ Padoru

3 0
3 years ago
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