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shtirl [24]
2 years ago
7

CAN SOMEONE PLEASE HELP ME

Mathematics
1 answer:
Evgesh-ka [11]2 years ago
6 0

Answer:

BDE- 85

EDG- 50

FDG- 60

CDA- 85

Step-by-step explanation:

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0.31 repeating as a fraction
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I believe its 31/100! <span>To write 0.3111 as a fraction you have to write 0.3111 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.</span>

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I’m stuck and I would really like your help.
Neporo4naja [7]

Answer:

Answer: 1/12

Step-by-step explanation:

2/5x-4=8-3/5x.

We want to tank x out of the denominator by multiplying x on both sides.

2/5-4x=8x-3/5

Now we simplify

-12x=-1

x=1/12

Put x in the equation to check it

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Make V the subject of the formula E=mv2/2
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v = ± \sqrt{\frac{2E}{m} }

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3 years ago
Please help. Find the area and the perimeter of the shaded regions below. Give your answer as a completely simplified exact valu
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Answer:

Area = (18 + 4.5π) cm²

Perimeter = (6√2 + 12 + 3π) cm

Step-by-step explanation:

The shaded region given is made up of triangle ABC and a semicircle

AB = BC = 6 cm (note that the triangle is a portion of a square)

Diameter of semi-circle (d) = BC = 6cm

Radius (r) = ½*6 = 3 cm

==>Area of the shaded region in terms of π

Area of shaded region = area of triangle + area of semicircle

Area = ½*a*b + ½*πr²

Area = ½*6*6 + ½*π3²

Area = 18 + ½*π9

Area = 18 + 4.5π

<em>Area of the shaded portion = (18 + 4.5π) cm²</em>

==>Perimeter of shaded region in terms of π

Perimeter of shaded region = perimeter of triangle + perimeter of semicircle

= Sum of all sides of the triangle + ½πd

Sides of triangles are AB = 6 cm, BC = 6 cm

Use Pythagorean theorem to find side AC:

AC² = AB² + BC²

AC² = 6² + 6² = 36 + 36 = 72

AC = √72 cm

Perimeter of shaded triangle = √72 + 6 + 6 = √72 + 12 = (6√2 + 12) cm

Perimeter of semicircle = ½*πd = ½π6

= 3π

<em>Perimeter of the whole shaded region in terms of π = (6√2 + 12 + 3π) cm</em>

<em></em>

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