Answer:
P could be any number if (4p+12) doesn't equal to number
Step-by-step explanation:
Answer:

See explanation below.
Step-by-step explanation:
For this case we define first some notation:
A= A new training program will increase customer satisfaction ratings
B= The training program can be kept within the original budget allocation
And for these two events we have defined the following probabilities

We are assuming that the two events are independent so then we have the following propert:

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

And using the De Morgan laws we know that:

So then we can write the probability like this:

And using the complement rule we can do this:

Since A and B are independent we have:

And then our final answer would be:

The correct option is B. Distributive property
Given,
On solving the above equation,
multiplying both sides by 3 we, get

now subtracting 21 from both the sides,

dividing both the sides by 2 we get,

Since in the above steps we follow all the giving property except the distributive property.
Hence the correct option is B. Distributive property.
For more details follow the link:
brainly.com/question/13130806
Answer:
34 m²
Step-by-step explanation:
Answer:
<h2>a = 400/21, b = 580/21</h2>
Step-by-step explanation:
Small triangles are similar. Therefore, the sides are proportional
<em>cross multiply</em>
<em>divide both sides by 21</em>

For b, we can use the Pythagorean theorem:
