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vlabodo [156]
3 years ago
8

A survey of a group’s viewing habits over the last year revealed the following information: (i) 28% watched gymnastics (ii) 29%

watched baseball (iii) 19% watched soccer (iv) 14% watched gymnastics and baseball (v) 12% watched baseball and soccer (vi) 10% watched gymnastics and soccer (vii) 8% watched all three sports. Calculate the percentage of the group that watched none of the three sports during the last year. (A) 24% (B) 36% (C) 41% (D) 52% (E) 60%

Mathematics
1 answer:
almond37 [142]3 years ago
3 0

Answer: D) 52%

Step-by-step explanation:

G = gymnastics

B = baseball

S = soccer

G = 28%

BA = 29%

S = 19%

G and BA = 14%

BA and S = 12%

G and S = 10%

GBS = 8%

So, as we can see at the Venn diagram attached (consider every number in %)

GBS = 8

A = G and S - GBS = 10 - 8 = 2

B = G and BA - GBS = 14 - 8 = 6

C = BA and S - GBS = 12 - 8 = 4

Only G = G - A - B - GBS = 28 - 2 - 6 - 8 = 12

Only BA = BA - B - C - GBS = 29 - 6 - 4 - 8 = 11

Only S = S - A - C - GBS = 19 - 2 - 4 - 8 = 5

So, 2+6+4+12+11+5+8 = 48

100 - 48 = 52%

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Step-by-step explanation:

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Michelle's mother bought 7 large pizzas for her birthday party. Each large pizza is cut into eighths. if 5/8 of the total slices
nirvana33 [79]
So we know that there are 8 slices per large pizza (7), so a total of 56 slices
we would set up a proportion
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3 years ago
Need help pls<br>thank you in advance ​
ira [324]

Answer:

<h3><u>Mean</u></h3>

<u />

\textsf{Mean}\:\overline{X}=\sf \dfrac{\textsf{sum of all the data values}}{\textsf{total number of data values}}

\implies \sf Mean\:(Nilo)=\dfrac{5+6+14+15}{4}=\dfrac{40}{4}=10

\implies \sf Mean\:(Lisa)=\dfrac{8+9+11+12}{4}=\dfrac{40}{4}=10

<h3><u>Standard Deviation</u></h3>

\displaystyle \textsf{Standard Deviation }s=\sqrt{\dfrac{\sum X^2-\dfrac{(\sum X)^2}{n}}{n-1}}

\begin{aligned}\displaystyle \textsf{Standard Deviation (Nilo)} & =\sqrt{\dfrac{(5^2+6^2+14^2+15^2)-\dfrac{(5+6+14+15)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{482-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{82}{3}}\\\\& = 5.23\end{aligned}

\begin{aligned}\displaystyle \textsf{Standard Deviation (Lisa)} & =\sqrt{\dfrac{(8^2+9^2+11^2+12^2)-\dfrac{(8+9+11+12)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{410-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{10}{3}}\\\\& = 1.83\end{aligned}

<h3><u>Summary</u></h3>

Nilo has a mean score of 10 and a standard deviation of 5.23.

Lisa has a mean score of 10 and a standard deviation of 1.83.

The <u>mean</u> scores are the <u>same</u>.

Nilo's standard deviation is higher than Lisa's.  Therefore, Nilo's test scores are more <u>spread out</u> that Lisa's, which means Lisa's test scores are more <u>consistent</u>.

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She had a down payment of $225, so that added on becomes $1305.

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0.0875 x 100 = 8.75% increase.

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