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3 years ago

Which equation has an a-value of –2, a b-value of 1, and a c-value of 3?

Mathematics

2 answers:

12345 [234]3 years ago

6 0

Answer:

1. $0=-2x^{2} +x+3$

Step by step explanation:

We are asked to find which of the given equation has our given coefficient values.

Since we know that in quadratic equations a is quadratic coefficient, b is linear coefficient and c is our constant term.

Let us see our given equations one by one.

1. $0=-2x^{2} +x+3$

We can see that coefficient of quadratic equation in our given option are:

a (quadratic coefficient)=-2

b (linear coefficient)= 1

c (constant) =3

Therefore, 1st option is correct choice.

2. $0=2x^{2} +x+3$

We can see that coefficient of quadratic equation in our given option are:

a (quadratic coefficient)=2

b (linear coefficient)= 1

c (constant) =3

Therefore, 2nd option is incorrect.

3. $0=-2x^{2} +3$

We can see that coefficient of quadratic equation in our given option are:

a (quadratic coefficient)=-2

b (linear coefficient)= 0

c (constant) =3

Therefore, 3rd option in incorrect as well.

4. $0=2x^{2} -x+3$

We can see that coefficient of quadratic equation in our given option are:

a (quadratic coefficient)=2

b (linear coefficient)= -1

c (constant) =3

Therefore, 4th option is incorrect too.

weeeeeb [17]3 years ago

3 0

The correct answer would be: 0 = <span>-2x2 + x + 3.</span>

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Answer:

$\chi^2 =\frac{132-1}{121} 114.49 =123.952$

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

$n=132$ represent the sample size

$\alpha$ represent the confidence level

$s^2 =10.7^2 =114.49$ represent the sample variance obtained

$\sigma^2_0 =11^2=121$ represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is violated, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 121$

Alternative hypothesis: $\sigma^2$

Calculate the statistic

For this test we can use the following statistic:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

$\chi^2 =\frac{132-1}{121} 114.49 =123.952$

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 131. And since is a right tailed test the p value would be given by:

$p_v =P(\chi^2$

In order to find the p value we can use the following code in excel:

"=1-CHISQ.DIST(123.952,131,TRUE)"

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