Question

Which equation has an a-value of –2, a b-value of 1, and a c-value of 3?

Answer 1

Answer:

1. $0=-2x^{2} +x+3$

Step by step explanation:

We are asked to find which of the given equation has our given coefficient values.

Since we know that in quadratic equations a is quadratic coefficient, b is linear coefficient and c is our constant term.

Let us see our given equations one by one.

1. $0=-2x^{2} +x+3$

We can see that coefficient of quadratic equation in our given option are:

a (quadratic coefficient)=-2

b (linear coefficient)= 1

c (constant) =3

Therefore, 1st option is correct choice.

2. $0=2x^{2} +x+3$

We can see that coefficient of quadratic equation in our given option are:

a (quadratic coefficient)=2

b (linear coefficient)= 1

c (constant) =3

Therefore, 2nd option is incorrect.

3. $0=-2x^{2} +3$

We can see that coefficient of quadratic equation in our given option are:

a (quadratic coefficient)=-2

b (linear coefficient)= 0

c (constant) =3

Therefore, 3rd option in incorrect as well.

4.  $0=2x^{2} -x+3$

We can see that coefficient of quadratic equation in our given option are:

a (quadratic coefficient)=2

b (linear coefficient)= -1

c (constant) =3

Therefore, 4th option is incorrect too.

Answer 2

The correct answer would be: 0 = -2x2 + x + 3.