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4 years ago

15

How do write a word problem for the following equation:

1 answer:

lozanna [386]4 years ago

7 0

Three and a half divided by seven-eighth equals seven over two times eight over seven equals fifty over fourteen equals four

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How to find square root ?

Dominik [7]

To estimate a square root, find the two perfect squares the number is closest to, then continue with further decimals, i.e. if the question is square root of 5, it is between 4 and 9. As such, the answer is between 2 and 3. Alternatively, use a calculator for a quick estimation of many decimal points.

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3 years ago

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Need help with this question!!

Mekhanik [1.2K]

the answer is Y=3X+3

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3 years ago

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If anyone has seen my other post this is my last one, I just really need to bring up my grade and I’ll really appreciate your an

Ganezh [65]

Answer:

55 mph

Step-by-step explanation:

First hour: 40 mph

Second, Third, Fourth hours:

180 miles / 3 hours = 60 mph

Average: 40 (hour 1) + 60 (hour 2) + 60 (hour 3) + 60 (hour 4) = 220 / 4 hours = 55 mph average

I hope this helps!

6 0

3 years ago

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Can someone explain this step by step please

levacccp [35]

Answer:

2

Step-by-step explanation:

Since x=-2

-2+3y=4

Add 2 on both sides

3y=6

Divide 3 on both sides

y=2

3 0

3 years ago

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Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,

omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

<u>Pyramid A</u>

$s = 4$ -- base sides

$V = 36$ -- Volume

<u>Pyramid B</u>

$s = 6$ --- base sides

Required

Determine the volume of pyramid B <em>[Missing from the question]</em>

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

$V = \frac{1}{3} * B * h$

Where B represents the area of the base equilateral triangle, and it is calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

$B = \frac{1}{2} * s^2 * sin(60)$

$B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}$

$B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}$

$B = 4\sqrt 3$

The height is calculated from:

$V = \frac{1}{3} * B * h$

This gives:

$36 = \frac{1}{3} * 4\sqrt 3 * h$

Make h the subject

$h = \frac{3 * 36}{4\sqrt 3}$

$h = \frac{3 * 9}{\sqrt 3}$

$h = \frac{27}{\sqrt 3}$

To calculate the volume of pyramid B, we make use of:

$V = \frac{1}{3} * B * h$

Since the heights of both pyramids are the same, we can make use of:

$h = \frac{27}{\sqrt 3}$

The base area B, is then calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where

$s = 6$

So:

$B = \frac{1}{2} * 6^2 * sin(60)$

$B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}$

$B = 9\sqrt 3$

So:

$V = \frac{1}{3} * B * h$

Where

$B = 9\sqrt 3$ and $h = \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9 * 27$

$V = 81$

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3 years ago

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