All categories

3 years ago

What is the rate of change x y -2 -6 -1 -3 0 0

1 answer:

5 0

So you subtract their integers by starting from the bottom then coming up to the top. And you just put the numbers in your calculator. Once you’ve got your answer for X and Y, you multiply them both. Which will give you -9/3. Next you divide -9 by 3 and 3 divided by 3. Which will give you -3/1 and just rewrite it as -3. I don’t know if this helps but I hope it does :).

You might be interested in

What is the area of this figure?

Dmitrij [34]

Answer:

the area is 30

Step-by-step explanation:

area of triangle =base×height

so ,

base=7.5

height=4

why , shouldn't we take 5(or)6 as height because we shouldn't take slanting lengths as height.

so apply base and height in the formula

7.5×4=30

please follow me

6 0

2 years ago

Keisha has a total of 90 coins all of which are either dimes or quarters the total value of the coins is $13.50 find the number

OLga [1]

1 dime and 14 quarters

5 0

3 years ago

An inequality for m is no greater than 35

kirza4 [7]

Answer:

<em>m</em> ≤ 35

Step-by-step explanation:

The variable "m" is no greater than 35.

Note that "no greater" means that it can be up to the certain number (in this case, 35), but cannot exceed it. Your answer will be:

<em>m</em> is less than or equal to 35, or <em>m</em> ≤ 35.

5 0

2 years ago

In an experiment, the initial temperature of a solution is -5 °C. The solution is heated up at 3 °C per minute for 19 minutes an

Free_Kalibri [48]

Answer:

28°C

Step-by-step explanation:

First you do 3*19=57°C

-5+57= 52°C

then you do 4*6=24 °C

as its being cooled you takeaway

52-24=28°C

3 0

2 years ago

Determine the number of zeros of the function,<br> 4) y = 2x² + 12x + 17

katrin2010 [14]

<h2>Explanation:</h2><h2></h2>

The zeroes of a function are those values that touches the x-axis. In order to find those values we must set $y=0$ :

$0=2x^2+12x+17 \\ \\ \text{Using quadratic formula}: \\ \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ a=2 \\ \\ b=12 \\ \\ c=17 \\ \\ \\ x=\frac{-12 \pm \sqrt{12^2-4(2)(17)}}{2(2)} \\ \\ x=\frac{-12 \pm \sqrt{8}}{4} \\ \\ x=\frac{-12 \pm 2\sqrt{2}}{4} \\ \\ \\ \text{Two values}: \\ \\ x_{1}=\frac{-6 + \sqrt{2}}{2} \\ \\ x_{2}=\frac{-6 - \sqrt{2}}{2}$

Finally, there are two zeros of the function that are:

$\boxed{x_{1}=\frac{-6 + \sqrt{2}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-6 - \sqrt{2}}{2}}$

6 0

2 years ago