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Gelneren [198K]
3 years ago
6

What is the rate of change x y -2 -6 -1 -3 0 0

Mathematics
1 answer:
Natalka [10]3 years ago
5 0
So you subtract their integers by starting from the bottom then coming up to the top. And you just put the numbers in your calculator. Once you’ve got your answer for X and Y, you multiply them both. Which will give you -9/3. Next you divide -9 by 3 and 3 divided by 3. Which will give you -3/1 and just rewrite it as -3. I don’t know if this helps but I hope it does :).
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What is the common difference or common ratio for the sequence: 27, 9, 3, 1, 1/3, ...
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Answer:

It's dividing by 3 everytime, so 1/3

Step-by-step explanation:

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A table with 2 columns and 7 rows. The first row, x, has the entries, negative 4, negative 3, negative 2, negative 1, 0, 1. The
UNO [17]
H(x) has a constant output of –2.50.
As x increases, g(x) increases.
g(x) is greater than –2.50 for x values less than –1.
h(x) is less than –2.50 for x values greater than –2.
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3 years ago
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Solve for x.
aivan3 [116]
X^3 = 216

by taking cubic root for both  sides

\sqrt[3]{x^3} =  \sqrt[3]{216}

x = 6
7 0
4 years ago
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Can you please help me find the area? Thank you. :)))
Phoenix [80]

The figure shown in the picture is a rectangular shape that is missing a triangular piece. To determine the area of the figure you have to determine the area of the rectangle and the area of the triangular piece, then you have to subtract the area of the triangle from the area of the rectangle.

The rectangular shape has a width of 12 inches and a length of 20 inches. The area of the rectangle is equal to the multiplication of the width (w) and the length (l), following the formula:

A=w\cdot l

For our rectangle w=12 in and l=20 in, the area is:

\begin{gathered} A_{\text{rectangle}}=12\cdot20 \\ A_{\text{rectangle}}=240in^2 \end{gathered}

The triangular piece has a height of 6in and its base has a length unknown. Before calculating the area of the triangle, you have to determine the length of the base, which I marked with an "x" in the sketch above.

The length of the rectangle is 20 inches, the triangular piece divides this length into three segments, two of which measure 8 inches and the third one is of unknown length.

You can determine the value of x as follows:

\begin{gathered} 20=8+8+x \\ 20=16+x \\ 20-16=x \\ 4=x \end{gathered}

x=4 in → this means that the base of the triangle is 4in long.

The area of the triangle is equal to half the product of the base by the height, following the formula:

A=\frac{b\cdot h}{2}

For our triangle, the base is b=4in and the height is h=6in, then the area is:

\begin{gathered} A_{\text{triangle}}=\frac{4\cdot6}{2} \\ A_{\text{triangle}}=\frac{24}{2} \\ A_{\text{triangle}}=12in^2 \end{gathered}

Finally, to determine the area of the shape you have to subtract the area of the triangle from the area of the rectangle:

\begin{gathered} A_{\text{total}}=A_{\text{rectangle}}-A_{\text{triangle}} \\ A_{\text{total}}=240-12 \\ A_{\text{total}}=228in^2 \end{gathered}

The area of the figure is 228in²

8 0
1 year ago
Quick algebra 1 question for 50 points!
Naddika [18.5K]

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Option A

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