Answer:
length = 60 foot, width = 30 foot
Step-by-step explanation:
Area of rectangular part, A = 1800 ft²
Cost of fencing three sides is $ 6 per foot and cost of one side fencing is $18 per foot.
Let the length of the rectangle is l and the width of the rectangle is W.
Area = Length x width
A = L x W
1800 = L x W ...... (1)
Total cost of fencing, C = 6 x ( L + W + L) + 18 x W
C = 6 (2L + W) + 18 W
C = 12 L + 24 W
Substitute the value of W from equation (1),
in equation (2)


Differentiate both sides with respect to L:

Put it equal to zero for maxima and minima

L = 60 foot
and W = 30 foot
So, the costing is minimum for length = 60 foot and the width = 30 foot.
Taking logarithms, you get

Answer:
-12
Step-by-step explanation:
I promise it's right
Volume of sphere is 4πr³/3 and volume of cone is ⅓πr²h, where r is radius and h is cone height.
Vol of Kamila’s sphere 4π(216)/3=288π
Vol of cone=π(9)(9)/3=27π
Total number of cones is 288/27=32/3=10 complete cones.
How is 20/100 = 13...
Anyways, look at the two fractions.
20/100 and 80/100
Notice how 20 times 4 equals 80?
So maybe, 13 * 4 = 52.