The sum is y(4y − 1) + <span>(y + 5)2 = 4y² -y +y² +25 - 10y = 5y²-11y + 25
the answer is </span><span>5y2 − 11y + 25
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Answer:
The solution for the system of equations is
x=2,y=−2
Explanation:
4x−3y=14.....equation (1)
y=−3x+4.....equation (2)
Solving by substitution
Substituting equation 2 in equation 1
4x−3⋅(−3x+4)=14
4x+9x−12=14
13x=14+12
13x=26
x=2
Finding y by substituting x in equation 1
4x−3y=14
4⋅2−3y=14
8−3y=14
8−14=3y
3y=−6
y=−2
F(x)=∛x
The domain will be all real numbers.
Answer: A) all real numbers.
Ej: if x=-8 ⇒∛-8=-2