1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
e-lub [12.9K]
3 years ago
5

When are zeros significant in a value ?

Chemistry
2 answers:
Anika [276]3 years ago
6 0
This is a part of my homework tonight hope it helps!

ASHA 777 [7]3 years ago
5 0

Answer:

If the zero is between fwo nonzeros

Explanation:

You might be interested in
What is an example of equilibrium?
frez [133]

A good example of equilibrium would be the mixing of oil and water in a closed container.

<h3>What is chemical equilibrium?</h3>

Chemical equilibrium is a condition in which the concentrations of components of a chemical reaction remain unchanged and have no tendency to change.

Of all the options, the only one where the concentrations of the component reactants cannot change is a mixture containing oil and water in a closed container.

Oil and water are immiscible and thus, their concentrations remain constant.

More on chemical equilibrium can be found here: brainly.com/question/4289021

#SPJ1

5 0
2 years ago
Susan needs to simplify the expression shown below what should be her first step
Digiron [165]
Susan should follow PEMDAS,

Parentheses
Exponents
Multiplication
Division
Addition
Subtraction,

So, the first step should be, to solve the equation in the parentheses.

I hope this helps!
5 0
3 years ago
A chemist observes that a large molecule reacts as if it were much smaller. The chemist proposes that the molecule is folded in
nadezda [96]

Answer:

Hypothesis

Explanation:

The following steps are applicable when we wish to prove a specific fact:

  • a hypothesis is made; this is a statement that we provide after some observations and we wish to either prove or deny it;
  • multiple experiments are carried out in order to gather significantly substantial amount of data that can be then further analyzed and any tendencies can be noticed;
  • based on the data gathered, conclusions are made: we either prove or deny the hypothesis. If hypothesis is proved, it may become a theory over long time.

In the context of this problem, we're at the first step where we make a hypothesis.

6 0
3 years ago
Cual es el disolvente de acero
drek231 [11]

Answer:

I do not know what is the solvent for steel is. sorry

Explanation:

5 0
3 years ago
We want to calculate the concentrations of all species in a 0.58 M Na 2 SO 3 (sodium sulfite) solution. The ionization constants
NeX [460]

Explanation:

Reaction equation is as follows.

      Na_{2}SO_{3}(s) \rightarrow 2Na^{+}(aq) + SO^{2-}_{3}(aq)

Here, 1 mole of Na_{2}SO_{3} produces 2 moles of cations.

[Na^{+}] = 2[Na_{2}SO_{3}] = 2 \times 0.58

                                  = 1.16 M

[SO^{2-}_{3}] = [Na_{2}SO_{3}] = 0.58 M

The sulphite anion will act as a base and react with H_{2}O to form HSO^{-}_{3} and OH^{-}.

As,     K_{b} = \frac{K_{w}}{K_{a_{2}}}

                       = \frac{10^{-14}}{6.3 \times 10^{-8}}

                       = 1.59 \times 10^{-7}

According to the ICE table for the given reaction,

          SO^{2-}_{3} + H_{2}O \rightleftharpoons HSO^{-}_{3} + OH^{-}

Initial:        0.58             0              0

Change:     -x               +x             +x

Equilibrium: 0.58 - x     x               x

So,

        K_{b} = \frac{[HSO^{-}_{3}][OH^{-}]}{[SO^{2-}_{3}]}

 1.59 \times 10^{-7} = \frac{x^{2}}{0.58 - x}

        x^{2} = 1.59 \times 10^{-7} \times (0.58 - x)

                x = 0.0003 M

So,   x = [HSO^{-}_{3}] = [OH^{-}] = 0.0003 M

[SO^{2-}_{3}] = 0.58 - 0.0003

                     = 0.579 M

Now, we will use [HSO^{-}_{3}] = 0.0003 M

The reaction will be as follows.

              HSO^{2-}_{3} + H_{2}O \rightleftharpoons H_{2}SO_{3} + OH^{-}

Initial:   0.0003

Equilibrium:  0.0003 - x        x             x

              K_{b} = \frac{x^{2}}{0.0003 - x}

        K_{b} = \frac{K_{w}}{K_{a_{1}}}

                      = \frac{10^{-14}}{1.4 \times 10^{-2}}

                      = 7.14 \times 10^{-13}

Therefore,  7.14 \times 10^{-13} = \frac{x^{2}}{0.0003 - x}

As,  x <<<< 0.0003. So, we can neglect x.

Therefore,  x^{2} = 7.14 \times 10^{-13} \times 0.0003

                              = 0.00214 \times 10^{-13}

                     x = 0.0146 \times 10^{-6}

x = [OH^{-}] = [H_{2}SO_{3}] = 1.46 \times 10^{-8}

    [H^{+}] = \frac{10^{-14}}{[OH^{-}]}

                = \frac{10^{-14}}{0.0003}

                = 3.33 \times 10^{-11} M

Thus, we can conclude that the concentration of spectator ion is 3.33 \times 10^{-11} M.

5 0
3 years ago
Other questions:
  • What is a isotope ?
    15·2 answers
  • Why is the half-life of a radioisotope important for radioactive dating?
    12·2 answers
  • With a manual transmission, the speed of the vehicle determines
    8·1 answer
  • How many valence electrons are transferred from the calcium atom to iodine in the formation of the compound calcium iodide?
    6·1 answer
  • What is the Empirical Formula when the Molecular Formula is Sb17Br21
    9·1 answer
  • Which EMW can humans see?
    11·1 answer
  • If I have an unknown quantity of gas at a pressure of 1.2 atm, a volume of 77 liters, and a temperature of
    9·1 answer
  • An object at a distance of 30 cm from a concave mirror gets its image at the same point. The focal length of the mirror is​
    6·1 answer
  • Diffusion is the movement of solutes from an area of
    6·2 answers
  • How many grams of glucose (C6H12O6) are contained in 555 mL of a 1.77 M glucose solution?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!