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e-lub [12.9K]
4 years ago
5

When are zeros significant in a value ?

Chemistry
2 answers:
Anika [276]4 years ago
6 0
This is a part of my homework tonight hope it helps!

ASHA 777 [7]4 years ago
5 0

Answer:

If the zero is between fwo nonzeros

Explanation:

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Calculate the number of calories needed to increase the temperature of 50.0 g of copper metal from 21.0 degrees C to 75.0 degree
KonstantinChe [14]
<h3>Answer:</h3>

1031.4 Calories.

<h3>Explanation:</h3>

We are given;

Mass of the copper metal = 50.0 g

Initial temperature = 21.0 °C

Final temperature, = 75°C

Change in temperature = 54°C

Specific heat capacity of copper = 0.382 Cal/g°C

We are required to calculate the amount of heat in calories required to raise the temperature of the copper metal;

Quantity of heat is given by the formula,

Q = Mass × specific heat capacity × change in temperature

   = 50.0 g × 0.382 Cal/g°C × 54 °C

   = 1031.4 Calories

Thus, the amount of heat energy required is 1031.4 Calories.

4 0
3 years ago
What do you get when you mix lemons with gun powder
Viefleur [7K]
A very disgusting type of lemonade 

6 0
4 years ago
The dissolution of 0.200 l of sulfur dioxide at 19 °c and 745 mmhg in water yields 500.0 ml of aqueous sulfurous acid. The solut
aivan3 [116]

Answer:

Molarity=1.22\ M

Explanation:

Given:  

Pressure = 745 mm Hg

Also, P (mm Hg) = P (atm) / 760

Pressure = 745 / 760 = 0.9803 atm

Temperature = 19 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (19 + 273.15) K = 292.15 K  

Volume = 0.200 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9803 atm × 0.200 L = n × 0.0821 L.atm/K.mol × 292.15 K  

⇒n = 0.008174 moles

From the reaction shown below:-

H_2SO_3+2NaOH\rightarrow Na_2SO_3+2H_2O

1 mole of H_2SO_4 react with 2 moles of NaOH

0.008174 mole of H_2SO_4 react with 2*0.008174 moles of NaOH

Moles of NaOH = 0.016348 moles

Volume = 13.4 mL = 0.0134 L ( 1 mL = 0.001 L)

So,

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.016348}{0.0134}\ M

Molarity=1.22\ M

8 0
3 years ago
Ca3(PO4)2 + H2SO4 → CaSO4 + H3PO4<br><br> Balance this reaction if necessary
devlian [24]
<span>Ca3(PO4)2 + 3 H2SO4 = 3 CaSO4 + 2 H3PO4</span>
<span>Reaction type: double replacement
</span>
7 0
3 years ago
Read 2 more answers
How many moles of hydrogen are needed to completely react with 2 moles of nitrogen
Natali5045456 [20]
Assuming ammonia is the product of this reaction:

N2+3H2--->2NH3

2 mole N2 * (3 mol H2)/(1 mol N2)= 6 mol H2

You would need 6 mol of hydrogen gas to completely react with 2 mol of nitrogen. 
5 0
3 years ago
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