Here’s a simplified explanation.
The <em>protons</em> in the nucleus <em>repel each other</em>. The <em>neutrons provide the “glue”</em> that holds the nucleus together and prevents it from flying apart.
The “glue” is the strong nuclear force. It is strong but extremely short range. It falls off extremely rapidly as the p-n distance increases.
A <em>neon atom</em> has 10 protons. There are three stable isotopes, with 10, 11, and 12 neutrons.
With fewer than 10 protons, the glue is not strong enough to hold the nucleus together.
If there are more than 12 neutrons, the average p-n distance is great enough that the glue has again become too weak.
<em>Gold</em> has one stable isotope. It contains 79 protons and 118 neutrons.
If there are fewer than 118 neutrons, the proton repulsions will be too strong for the strong force. If there are more than 118 neutrons, the average p-n distance will be large enough that the glue will again be too weak to hold the nucleus toge
ther.
Atomic mass Ca = 40 a.m.u
1 mole Ca ----------- 40 g
2.5 mols Ca -------- ( mass Ca )
Mass Ca = 2.5 x 40 / 1
Mass Ca = 100 / 1
= 100 g of Ca
hope this helps!
Answer:
Option C. hydroxide ions (OH-).
Explanation:
A base is a substance which dissolves in water to produce hydroxide ion (OH-) as the only negative ion. It therefore means that a base contains more hydroxide ions (OH-).
Answer:
0. 414
Explanation:
Octahedral interstitial lattice sites.
Octahedral interstitial lattice sites are in a plane parallel to the base plane between two compact planes and project to the center of an elementary triangle of the base plane.
The octahedral sites are located halfway between the two planes. They are vertical to the locations of the spheres of a possible plane. There are, therefore, as many octahedral sites as there are atoms in a compact network.
The Octahedral interstitial void ratio range is 0.414 to 0.732. Thus, the minimum cation-to-anion radius ratio for an octahedral interstitial lattice site is 0. 414.
Number D both H and OH ions
