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Mazyrski [523]
3 years ago
6

How many valence electrons are transferred from the calcium atom to iodine in the formation of the compound calcium iodide?

Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
6 0

Answer:2

Explanation:because the compound is CaI2, Ca needs to lose 2 electrons and I needs to gain 1 electron to reach an octet and so there will be 2 I atoms therefore 2 electron transfer

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B. Chemical energy to start a chemical reaction
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Fill the three 3d subshells with the specified number of electrons.
lana66690 [7]

1. 5 electrons.

3d^{5}

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8 0
2 years ago
What is the net ionic equation for the precipitation reaction between BaCl2 and Na2So4? I know the answer ( Ba2+(aq) + SO42-(aq)
elixir [45]

Answer:

Net ionic equation:

Ba²⁺(aq) + SO₄²⁻(aq)  →   BaSO₄(s)

Explanation:

Chemical equation:

BaCl₂ +  Na₂SO₄   →   BaSO₄ + NaCl

Balanced Chemical equation:

BaCl₂(aq) +  Na₂SO₄(aq)   →   BaSO₄(s) + 2NaCl(aq)

Ionic equation:

Ba²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq)  →  BaSO₄(s)+ 2Na⁺(aq) + 2Cl⁻ (aq)

Net ionic equation:

Ba²⁺(aq) + SO₄²⁻(aq)  →   BaSO₄(s)

The Cl⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The BaSO₄ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

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