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timofeeve [1]
3 years ago
6

An object at a distance of 30 cm from a concave mirror gets its image at the same point. The focal length of the mirror is​

Chemistry
1 answer:
Nimfa-mama [501]3 years ago
3 0

The focal length of the mirror is 15 cm

From the question given above, the following data were obtained:

Object distance (u) = 30 cm

Image distance (v) = 30 cm

<h3>Focal length (f) =? </h3>

The focal length of the mirror can be obtained as follow:

\frac{1}{f} = \frac{1}{v} + \frac{1}{u} \\\\\frac{1}{f} = \frac{1}{30} + \frac{1}{30}\\\\\frac{1}{f} = \frac{2}{30} \\\\\frac{1}{f} = \frac{1}{15} \\\\

<h3>Invert </h3><h3>f = 15 cm</h3>

Therefore, the focal length of the mirror is 15 cm

Learn more: brainly.com/question/1392083

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When titrating a NaF(aq) solution with HCl(aq), the equivalence point will occur at a pH value ______ .
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At the equivalence point, the NaF completely reacts with the HCl

The correct option that gives the equivalence point when titrating NaF solution with HCl(aq), occur at a pH value is option c);

c) <u>Below 7 because it is determined by HF (aq)</u>

Reason:

The ionic equation of the reaction taking place in the titration is presented as follows;

  • NaF + HCl → HF + NaCl
  • Na⁺ (aq) + F⁻ (aq) + H⁺ (aq) + Cl⁻(aq) → HF (aq)+ Na⁺(aq) + Cl⁻(aq)

Therefore, by removing the spectator ions, we get;

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Therefore;

The net ionic equation is the formation of hydrofluoric acid, HF, which is a

weak acid, therefore, the pH value will be <u>below 7 because it is determined </u>

<u>by HF</u>

<u />

Learn more about equivalence point here: titration

brainly.com/question/2496608

brainly.com/question/14819792

brainly.com/question/23502649

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