Answer:
34.9 g/mol is the molar mass for this solute
Explanation:
Formula for boiling point elevation: ΔT = Kb . m . i
ΔT = Temperatures 's difference between pure solvent and solution → 0.899°C
Kb = Ebullioscopic constant → 0.511°C/m
m = molality (moles of solute/1kg of solvent)
i = 2 → The solute is a strong electrolyte that ionizes into 2 ions
For example: AB ⇒ A⁺ + B⁻
Let's replace → 0.899°C = 0.511 °C/m . m . 2
0.899°C / 0.511 m/°C . 2 = m → 0.879 molal
This moles corresponds to 1 kg of solvent. Let's determine the molar mass
Molar mass (g/mol) → 30.76 g / 0.879 mol = 34.9 g/mol
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Answer:
1.14kg of chalcopyrite
Explanation:
In 1 mole of chalcopyrite, CuFeS₂, there is 1 mole of Cu. Thus, to solve this question we need to convert the mass of pure Cu to moles using molar mass (Cu = 63.546g/mol). Then, the moles of Cu are equal to moles of chalcopyrite that must be converted to grams and then to kg (CuFeS₂: 183.54g/mol)
<em>Moles Cu:</em>
395g Cu * (1mol / 63.546g) = 6.216 moles Cu = 6.216 moles CuFeS₂
<em>Mass chalcopyirite:</em>
6.216 moles CuFeS₂ * (183.54g/mol) = 1140.9g
<em>In kilograms:</em>
1140.9g * (1kg / 1000g) =
<h3>1.14kg of chalcopyrite</h3>
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