Question

How many grams of glucose (C6H12O6) are contained in 555 mL of a 1.77 M glucose solution?

Answer 1

176.980176 g of glucose ($C_6H_{12}O_6$) are contained in 555 mL of a 1.77 M glucose solution.

What are moles?

A mole is defined as 6.02214076 × $10^{23}$ of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

$Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}$

$1.77 M = \frac{Moles \;solute}{0.555 L}$

mole solute = 0.98235 g/mol

$Moles = \frac{mass}{molar \;mass}$

$0.98235 g/mol = \frac{mass}{180.16 g/mol}$

mass = 176.980176 g

Hence, 176.980176 g of glucose ($C_6H_{12}O_6$) are contained in 555 mL of a 1.77 M glucose solution.

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