Answer:
Magnitude of electric field = E = q/Aε0
Explanation:
Consider plates are placed at a distance of d. As given in the question the charge stored on the plates have magnitude q and given by:
q = CV
And
V = q/C ……. (i)
The capacitance is given by the following equation:
C = Aε0/d ……. (ii)
Put equation (ii) in (i)
,
V = qd/ Aε0 …..(iii)
The electric field is defined as:
E = V/d …… (iv)
Put equation (iii) in (iv),
E = qd/ Aε0d
E = q/Aε0
Hence, the magnitude of electric field will be q/Aε0 .
They belong to the kingdom of Chordata
Power is the rate of doing work.
Its unit is joules/second.
That unit is used so often that a new word was adopted for it.
1 joule/sec = 1 watt
Can you give us the options…?
