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statuscvo [17]
3 years ago
11

Two carts collide on a low-friction track. Cart 1 has an initial momentum of +10 kg⋅m/sι^ and a final momentum of -5.0 kg⋅m/sι^

. If cart 2 has a final momentum of -7.0 kg⋅m/sι^ , what was its initial momentum?
Physics
2 answers:
Basile [38]3 years ago
6 0

According to the saving of the momentum, the total momentum before collision is equal to the total momentum after collision

<em><u>in symbols:</u></em>

<em>P_{i1}+P_{i2}=P_{f1}+P_{f2}</em>

thus

10+P_{i2}=(-5)+(-7)

then, the initial momentum of the second cart

P_{i2}=(-7)+(-5)+(10)=-23m/s

monitta3 years ago
4 0

Due to the Law of Conservation of Momentum we have;

P1i+P2i=P1f+P2f

10+P2i=-5-7

P2i=-22

So Cart 2 initial momentum is -22kg*m/s^2

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Answer:

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3 0
3 years ago
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This is a perfect place to remind you of the old unbelievable story,
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