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SIZIF [17.4K]
4 years ago
9

Two equal forces act on two different objects, one of which has a mass ten times as large as the other. Will the more massive ob

ject have a larger acceleration, an equal acceleration, or a smaller acceleration than the less massive object? Explain.
Physics
1 answer:
Vesnalui [34]4 years ago
6 0
Smaller acceleration due to the force being applied to both objects being equal so the object with the larger mass will have a smaller acceleration
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19. The work done by a magnetic field on a charged particle moving in it is:
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Answer:

The work done by a magnetic feild on a chraged particle moving in it is zero

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A piece of solid copper, at 10oC, is dropped into a graduated cylinder of 100°C water. Which statement BEST describes the change
enot [183]

Answer:

D

Explanation:

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4 years ago
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A roundabout is a type of playground equipment involving a large flat metal disk that is able to spin about its center axis. A r
Zina [86]

Answer:

116.1 kgm²/s

1.12718 rad/s

Decreases

Explanation:

m = Mass of girl = 43 kg

M = Mass of roundabout = 120 kg

v = Velocity of roundabout = 2.7 m/s

r = Radius of roundabout = 1 m = R

I = Moment of inertia

Her angular momentum

L_i=mvr\\\Rightarrow L_i=43\times 2.7\times 1\\\Rightarrow L_i=116.1\ kgm^2/s

Magnitude of angular momentum is 116.1 kgm²/s

Here the angular momentum is conserved

L_f=L_i\\\Rightarrow I\omega=L_i\\\Rightarrow (\frac{1}{2}MR^2+mr^2)\omega=116.1\\\Rightarrow \omega=\frac{116.1}{\frac{1}{2}\times 120\times 1^2+43\times 1^2}\\\Rightarrow \omega=1.12718\ rad/s

Angular speed of the roundabout is 1.12718 rad/s

Initial kinetic energy

K_i=\frac{1}{2}mv^2\\\Rightarrow K_i=\frac{1}{2}43\times 2.7^2\\\Rightarrow K_i=156.735\ J

Final kinetic energy

K_f=\frac{1}{2}I\omega^2\\\Rightarrow K_f=\frac{1}{2}\times (\frac{1}{2}\times 120\times 1^2+43\times 1^2)\times 1.12718^2\\\Rightarrow K_f=65.43253\ J

The overall kinetic energy decreases as can be seen. This loss is converted to heat.

5 0
3 years ago
In a ballistics test, a 24 g bullet traveling horizontally at 1300 m/s goes through a 25-cm-thick 360 kg stationary target and e
MaRussiya [10]

Answer:

A)0.00022s b)40363.6N c) 0.025m/s

Explanation:

Mass = 24g = 0.024kg, distance though the target = thickness of the target = 25cm = 0.25m

Initial speed of the bullet = 1300m/s, final speed = 930m/s

Using equation of motion

Distance = 1/2(vf+vi)*t (time in seconds)

t = 0.25*2/(1300+930) = 0.00022s

B) force exerted on the body

F = ma = m* (vf-vi)/t = 0.024*(930-1300)/0.00022

F = -40363N, it is negative because the body decelerated during this motion

C) using law of conservation of momentum,

M1*U1+ M2*U2(M2and U1 are the mass and initial speed of the body) = M1V1+ M2V2

The target was at rest so initial speed U2 = 0

0.024*1300 + 360*0 = 0.024*930 + 360*V2

31.2 = 22.32+360*V2

31.2-22.33 = 360*V2

V2 = 8.88/360 = 0.025m/s

8 0
3 years ago
Which organelle packages materials and distributes them throughout the cell?
kakasveta [241]

Answer:

i think its the golgi body tbh

Explanation:

hope this helps

5 0
4 years ago
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