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klio [65]
3 years ago
15

Work the following pricing problems for services rendered. (For all calculations use hundredths.)

Mathematics
1 answer:
Lesechka [4]3 years ago
3 0

Answer:

Hourly Rate = $12.22 per hour

Step-by-step explanation:

\text{Labor Time = }4\tfrac{1}{2}=4.5\thinspace{ hours}

Overhead Rate = 95%

Retail price of parts = $134.75

Total cost of job = $241.98

Cost of labor = Total cost - Retail price

                      = 241.98 - 134.75

                      = $107.23

Now, labor works for 4.5 hours and ears a total amount of $107.23

\implies\text{Amount earned in one hour or hourly rate = }\frac{107.23}{4.5}\\\\\implies \text{Hourly rate = }\$23.83\text{ per hour}

Now, Labor will get 95% overhead rate

⇒ The labor is getting 100% already but an overhead of 95% is also given

\text{So, Hourly Rate = }\frac{23.83}{1+0.95}\\\\\bf\implies\textbf{Hourly Rate = }\$12.22\textbf{ per hour}

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Answer:

A

Step-by-step explanation:

22 successes out of a group of 40 means 22/40 were good. Now, simplify 22/40. Both can be divided by 2.

22/2 = 11

40/2 = 20

Now you have 11/20. Put this in decimal form and you have 0.55

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3 years ago
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Answer:

8. x = 16

9. x = 10

14.

m ∠RSU = 130°

m ∠UST = 50°

15.

m ∠RSU = 124°

m ∠UST = 56°

Step-by-step explanation:

8.

Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF

That is , (x + 15)° = 31°

                x = 31 - 15 =  16

9.

Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF

That is ,

           (6x - 4)° = 56°

            6x = 56 + 4

               6x = 60

                 x = 10

14.

13x + 5x = 180°                       [straight line angles ]

18x = 180

x = 10

m ∠RSU = 130°

m ∠UST = 50°

15.

4x + 12 + 2x = 180°                       [ straight line angles]

6x = 180 - 12

6x = 168

x = 28

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m ∠UST = 2(28) = 56°

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2 years ago
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Answer: There is a difference of $ 1.0228.

Explanation: Given, initial amount or principal = $ 1000,

Time= 5 years and given compound rate of interest = $3.7%

Now, Since the amount in compound continuously,

A= Pe^{rt} , where, r is the rate of compound interest, P is the principal amount and t is the time.

Here, P=$ 1000, t=5 years and r= $3.7%,

Thus, amount in compound continuously ,  A=1000e^{3.7\times5/100}

⇒A=1000e^{18.5}=1000\times 1.20321844013=1203.21844013

Therefore, interest in this compound continuously rate =1203.21844013-1000=203.21844013

now, Since the amount in compound quarterly,

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So, the difference in these interests=203.21844013-202.19567617=1.02276396 ≈1.0228                                                  

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