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3 years ago

A radioactive nuclide that is used to label blood platelets has 49 protons and 62 neutrons. Which is the symbol of this nuclide?

2 answers:

6 0

From among the subatomic particles available, we determine which element is presented by using the number of protons. The 49th element in the periodic table is Indium (In). The chemical symbol is In-62. 62 is the number representing the number of neutrons .

Answer: In-62

dlinn [17]3 years ago

6 0

Answer: The nuclide is $_{49}^{111}\textrm{In}$

Explanation: We are given a radioactive nuclide having 46 protons and 62 neutrons.

In an element,

Atomic number = number of protons = number of electrons

Hence, Atomic number = 49

and, Atomic mass = number of neutrons + number of protons

Atomic mass = 62 + 49 = 111

An element having atomic number 49 is Indium (In).

Representing an element = $_{Z}^{A}\textrm{X}$ where, X = element

A = Atomic mass

Z = Atomic number

Radioactive isotope used to label blood platelets is $_{49}^{111}\textrm{In}$

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3 years ago

A piece of lithium is placed on the surface of some water in a beaker. hydrogen is given off. Lithium hydroxide is formed. What

Gala2k [10]

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8 0

3 years ago

Determine the empirical formula of a compound containing 48.38 grams of carbon, 6.74 grams of hydrogen, and 53.5 grams of oxygen

Darya [45]

Answer: The empirical formula of the compound becomes $CH_2O$

Explanation:

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

We are given:

Mass of C = 48.38 g

Mass of H = 6.74 g

Mass of O = 53.5 g

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Molar mass of C = 12 g/mol

Molar mass of H = 1 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

$\text{Moles of C}=\frac{48.38g}{12g/mol}=3.023 mol$

$\text{Moles of H}=\frac{6.74g}{1g/mol}=6.74 mol$

$\text{Moles of O}=\frac{53.5g}{1g/mol}=3.34 mol$

Step 2: Calculating the mole ratio of the given elements.

Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 3.023 moles

$\text{Mole fraction of C}=\frac{3.023}{3.023}=1$

$\text{Mole fraction of H}=\frac{6.74}{3.023}=2.23\approx 2$

$\text{Mole fraction of O}=\frac{3.34}{3.023}=1.105\approx 1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 2 : 1

Hence, the empirical formula of the compound becomes $CH_2O$

5 0

3 years ago

Select all the correct images Select the atoms that belong to the same element

mezya [45]

Answer: Atoms with 11 protons, 10 neutrons and 11 electrons belong to the same element with 11 protons, 12 neutrons and 11 electrons.

Explanation:

Elements that contain same number of valence electrons belong to the same group. This is because they will have same reactivity (or properties) due to which they lie in the same group.

For example, element with 11 protons, 10 neutrons and 11 electrons is same as the element with 11 protons, 12 neutrons and 11 electrons.

Hence, both these atoms belong to the same element.

Thus, we can conclude that atoms with 11 protons, 10 neutrons and 11 electrons belong to the same element with 11 protons, 12 neutrons and 11 electrons.

3 0

3 years ago