A radioactive nuclide that is used to label blood platelets has 49 protons and 62 neutrons. Which is the symbol of this nuclide?
2 answers:
Answer: The nuclide is
Explanation: We are given a radioactive nuclide having 46 protons and 62 neutrons.
In an element,
Atomic number = number of protons = number of electrons
Hence, Atomic number = 49
and, Atomic mass = number of neutrons + number of protons
Atomic mass = 62 + 49 = 111
An element having atomic number 49 is Indium (In).
Representing an element = where, X = element
A = Atomic mass
Z = Atomic number
Radioactive isotope used to label blood platelets is
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Answer : The work done on the surroundings is, 709.1 Joules.
Explanation :
The formula used for isothermally irreversible expansion is :
where,
w = work done
= external pressure = 1.00 atm
= initial volume of gas = 1.00 L
= final volume of gas = 8.00 L
Now put all the given values in the above formula, we get :
The work done by the system on the surroundings are, 709.1 Joules. In this, the negative sign indicates the work is done by the system on the surroundings.
Therefore, the work done on the surroundings is, 709.1 Joules.
The chemical formula for ammonium carbonate is (NH₄)₂CO₃ .
It shows that one mole of ammonium carboonate contains two mole of ammonium ion that is NH₄⁺ .
Number of moles of ammonium carbonate , n=
Given mass of the ammonium carbonate=0.557 g
Molar mass of the ammonium carbonate= 96.086 g/mol
Number of moles of ammonium carbonate,
=0.0057 mol (NH₄)₂CO₃
0.0057 mol (NH₄)₂CO₃=0.0057×2 of NH₄⁺
=0.0114 of NH₄⁺