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olya-2409 [2.1K]
3 years ago
5

A radioactive nuclide that is used to label blood platelets has 49 protons and 62 neutrons. Which is the symbol of this nuclide?

Chemistry
2 answers:
Drupady [299]3 years ago
6 0
From among the subatomic particles available, we determine which element is presented by using the number of protons. The 49th element in the periodic table is Indium (In). The chemical symbol is In-62. 62 is the number representing the number of neutrons .

Answer: In-62
dlinn [17]3 years ago
6 0

Answer: The nuclide is _{49}^{111}\textrm{In}

Explanation: We are given a radioactive nuclide having 46 protons and 62 neutrons.

In an element,

Atomic number = number of protons = number of electrons

Hence, Atomic number = 49

and, Atomic mass = number of neutrons + number of protons

Atomic mass = 62 + 49 = 111

An element having atomic number 49 is Indium (In).

Representing an element = _{Z}^{A}\textrm{X} where, X = element

A = Atomic mass

Z = Atomic number

Radioactive isotope used to label blood platelets is _{49}^{111}\textrm{In}

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How many moles are in 3.24 x 1020 particles of lead? (show work plz)
lesya [120]
<h3>Answer:</h3>

0.000538 mol Pb

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.24 × 10²⁰ particles Pb (lead)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                                  \displaystyle 3.24 \cdot 10^{20} \ particles \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ particles \ Pb})
  2. Multiply/Divide:                                                                                               \displaystyle 0.000538 \ mol \ Pb

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

Our final answer is in 3 sig figs, no need to round.

7 0
3 years ago
Identify limiting and excess reagents when 25g of nitrogen reacts with 25g of hydrogen. How many grams of ammonia gas are formed
Makovka662 [10]

Answer:

Nitrogen is limiting reactant while hydrogen is in excess.

Explanation:

Given data:

Mass of N₂ = 25 g

Mass of H₂ = 25 g

Mass of ammonia formed = ?

Solution:

Chemical equation:

N₂ + 3H₂    →     2NH₃

Number of moles of Nitrogen:

Number of moles = mass/ molar mass

Number of moles = 25 g/ 28 g/mol

Number of moles = 0.89 mol

Number of moles of hydrogen:

Number of moles = mass/ molar mass

Number of moles = 25 g/ 2 g/mol

Number of moles = 12.5 mol        

Now we will compare the moles of both reactant with ammonia.

                   H₂            ;             NH₃

                    3             :              2

                    12.5        :            2/3×12.5 = 8.3

                 

                   N₂            ;             NH₃

                    1              :              2

                    0.89        :            2×0.89 = 1.78

The number of moles of ammonia produced by nitrogen are less thus nitrogen is limiting reactant while hydrogen is in excess.

7 0
3 years ago
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