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Paraphin [41]
3 years ago
8

What do chemists study

Chemistry
2 answers:
Contact [7]3 years ago
5 0

Answer: Chemist study properties of matter at the level of atoms and molecules. They measure proportions and reaction rate in order to see how unfamiliar substance and how they behave

Explanation:

ANTONII [103]3 years ago
3 0

Answer:

Chemists investigate the properties of matter at the level of atoms and molecules. They measure proportions and reaction rates in order to understand unfamiliar substances and how they behave, or to create new compounds for use in a variety of practical applications.

Explanation:

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What evidence did Alfred wegener use to support his theory of continental drift? I need help!!
Eddi Din [679]
Tokeydrift bro he saw that movie and went errrrrrr with his car
5 0
3 years ago
20 milliliters of water are poured into a graduated cylinder. A sample of metal is added. The water rises to the 32-milliliter l
Sindrei [870]

Answer:

12

Explanation:

32-20= 12

This is because when the metal is added it adds to the volume of the liquid hence to find the metal itself subtract the final volume from Intel volume

5 0
3 years ago
Read 2 more answers
What happens to a nitrogen atom when heated
KATRIN_1 [288]

Answer: Nitrogen normally exists as two-atom molecules in the form of a gas at room temperature.

Explanation:

4 0
3 years ago
For the reaction C+2H 2 —->CH 4 calculate the percent yield if 98 g of methane is produced when 100. g of carbon reacts with
skelet666 [1.2K]

The percent yield : 73.5%

<h3>Further explanation</h3>

Given

Reaction

C+2H₂⇒CH₄

Required

The percent yield

Solution

mol of Carbon(as a limiting reactant) :

\tt \dfrac{100}{12}=8.3

mol CH₄ based on C, and from equation mol ratio C : CH₄, so mol CH₄ = 8.3

Mass of Methane(theoretical yield) :

\tt mass=mol\times MW\\\\mass=8.3\times 16=133.3~g

\tt \%~yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{98}{133.3}\times 100\%=73.5\%

4 0
3 years ago
What is the mass of 0.7891 mol of ferric oxide (Fe2O3)?
Lubov Fominskaja [6]

The mass  of 0.7891 mol  of  ferric  oxide (Fe2O3)  is  125.94 grams


 <u><em>calculation</em></u>

mass of Fe2O3 is calculated using   moles   Fe2O3/ molar  mass of Fe2O3  formula

moles of Fe2O3  = 0.7891  moles

molar  mass  of Fe2O3=   (55.8 x2)  + (16 x3)  =159.6 g/mol


mass is therefore =0.7891 mol  x 159.6 g/mol=125.94 grams

6 0
3 years ago
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